- #1

DrClapeyron

## Main Question or Discussion Point

Looking at the units involved with the Ohm's equation and the capacitance equation I found this much:

V=iR

C=q/V

So...

C=q/(iR) and i=q/t

so...

C=t/R and R/t=1/C

Basic stuff. So capacitance is proportional to the inverse of the resistance. This would help explain why resistors in series add up (R + R + R....) and capacitors in series inversely add up (1/C + 1/C + 1/C...). And RC=t, and of course this relationship is used in calculating discharge of an RC circuit.

So what I would like to say is that a capacitor is a series of resistors that adds up to an non-ohmic resistor: two conductors separeted by an insulator. The resistance in the insulator will vary in a non-linear way as it discharges at a critical voltage. Is this a correct way of looking at the relationship between capacitance and resistance?

V=iR

C=q/V

So...

C=q/(iR) and i=q/t

so...

C=t/R and R/t=1/C

Basic stuff. So capacitance is proportional to the inverse of the resistance. This would help explain why resistors in series add up (R + R + R....) and capacitors in series inversely add up (1/C + 1/C + 1/C...). And RC=t, and of course this relationship is used in calculating discharge of an RC circuit.

So what I would like to say is that a capacitor is a series of resistors that adds up to an non-ohmic resistor: two conductors separeted by an insulator. The resistance in the insulator will vary in a non-linear way as it discharges at a critical voltage. Is this a correct way of looking at the relationship between capacitance and resistance?