Can I use polar coordinates in a triple integral?

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Discussion Overview

The discussion revolves around the use of polar coordinates in the context of triple integrals, specifically whether it is permissible to express a domain of integration in polar coordinates instead of Cartesian coordinates. Participants explore the implications of using different coordinate systems for integration, particularly in relation to circular domains.

Discussion Character

  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants argue that the problem requires the use of Cartesian coordinates (x, y, z) for defining the domain of integration, suggesting that polar coordinates (r, θ, φ) should not be used.
  • Others propose that polar coordinates can be beneficial for integration over circular domains, indicating that they facilitate calculations.
  • A participant mentions that polar coordinates are a special case that can simplify calculations in the x-y plane, as stated by their professor.
  • There is a suggestion that one could start in polar coordinates and then convert to Cartesian coordinates, as long as the change of variables formula is applied correctly.
  • Some participants express uncertainty about whether polar coordinates can be used when specifically asked for Cartesian coordinates, leading to further clarification requests.

Areas of Agreement / Disagreement

Participants generally disagree on whether polar coordinates can be used in place of Cartesian coordinates for the problem at hand. Some maintain that Cartesian coordinates must be used, while others suggest that polar coordinates may be appropriate under certain conditions.

Contextual Notes

There are unresolved questions regarding the definitions and conditions under which polar coordinates can be applied in the context of triple integrals. The discussion reflects varying interpretations of the problem requirements and the role of coordinate transformations.

queenstudy
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if i am being asked to write the domain of integration in a triple integral problem in a cartesian form , may i used polar coordinates to express instead of x and y? thank you
 
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"Cartesian" form in a triple integral means x, y, and z.
"Polar" is another form (meaning r, theta, and phi).
So I would conclude that you're not supposed to use polar coordinates.
 
No, you have to use the change of variables formula.
 
I like Serena said:
"Cartesian" form in a triple integral means x, y, and z.
"Polar" is another form (meaning r, theta, and phi).
So I would conclude that you're not supposed to use polar coordinates.

but from what i took in class polar coordinates are r and theta only let me explain my problem more.
if i have a disk of radius 1 covering the (xOy) axis and i want to to integration, it is better to use polar coordinates than cartesian coordinates , but my proffesor told me that polar coordinates are part of cartesian by by saying that x=rcosθ and y=rsinθ
your thoughts please and thank you very much for helping me out
 
Yes, if you want to do a (double) integration on a circular disk, it's usually best to use polar coordinates to calculate the result.

But that is not what is asked in your problem statement.
Your problem statement asks to define the domain (of a circular disk I presume?) in terms of cartesian coordinates (meaning x and y).

After you have done that, it may be expedient for a next part of your problem to convert to polar coordinates to actually calculate the integral.
 
so let me ask this one last time , if you don't mind , when i am askled to find any integration by cartesian coordinates , may i use the polar coordinates or not?? and thank you very very much serena
 
It depends on how the problem is stated exactly.
 
I have any domain D and i want to express the triple integral using cartesian coordinates??
 
queenstudy said:
I have any domain D and i want to express the triple integral using cartesian coordinates??

Then you have no choice.
It has to be x and y.

Btw, I presume you meant double integral?
Otherwise your problem would be 3-dimensional.
 
  • #10
I like Serena said:
Then you have no choice.
It has to be x and y.

Btw, I presume you meant double integral?
Otherwise your problem would be 3-dimensional.


no i mean triple integral
yes it is triple integral does it make a difference?
 
  • #11
A triple integral in cartesian coordinates requires you to use x, y, and z.

It means that you would typically integrate over a sphere or a cylinder, which you can do with x, y, and z.
 
  • #12
but polar coordinates are a special case used to facilitate our calculations in the x and y-axis that what our proffessor said
 
  • #13
So you could for instance start out in polar coordinates and convert them to cartesian coordinates, since that is what is requested.
 
  • #14
queenstudy said:
so let me ask this one last time , if you don't mind , when i am askled to find any integration by cartesian coordinates , may i use the polar coordinates or not?? and thank you very very much serena

Yes, you can use polar coordinates.

What your professor told you to use is the change of variables formula, by setting x = r sin(theta), etc. This defines a transformation from xyz space to r-theta-z space - thus the integral over, say, a cylinder in xyz space is equal to the integral over a box in r-theta-z space. The integral in r-theta-z space uses cartesian coordinates in that space.

Or in other words, the integral in terms of angles and radii (polar coords) becomes an integral in terms of cartesian coords.
 
  • #15
resolvent1 said:
Yes, you can use polar coordinates.

What your professor told you to use is the change of variables formula, by setting x = r sin(theta), etc. This defines a transformation from xyz space to r-theta-z space - thus the integral over, say, a cylinder in xyz space is equal to the integral over a box in r-theta-z space. The integral in r-theta-z space uses cartesian coordinates in that space.

Or in other words, the integral in terms of angles and radii (polar coords) becomes an integral in terms of cartesian coords.

thank very much the i will use polar coordinates to facilitate my calculations
 

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