Can Induction Prove the Equality of Cubic and Square Sums?

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SUMMARY

The discussion centers on proving the equality of the sum of cubes and the square of the sum of integers using mathematical induction. The user successfully verifies the base case for N=1, where 1^3 equals (1)^2. However, confusion arises during the induction step when attempting to prove the case for k+1, as discrepancies between the left-hand side (LHS) and right-hand side (RHS) terms are identified. The user seeks clarification on the equality and the correct approach to resolve the issue.

PREREQUISITES
  • Understanding of mathematical induction
  • Familiarity with summation notation
  • Knowledge of polynomial expressions
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the principles of mathematical induction in detail
  • Learn about the formula for the sum of cubes: \(\sum_{i=1}^n i^3 = \left(\frac{n(n+1)}{2}\right)^2\)
  • Explore algebraic identities related to summation
  • Practice proving other mathematical identities using induction
USEFUL FOR

Students studying mathematics, particularly those focusing on algebra and proof techniques, as well as educators looking for examples of induction proofs.

Trentonx
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Homework Statement



Prove by induction \sum\limits_{i=0}^n i^3 = (\sum\limits_{i=0}^N i)^2

Homework Equations


The Attempt at a Solution



So I used N=1 and found that indeed, 1^3 = (1)^2

Then I assumed it was valid up to some limit k, and tried to find it for k+1
(1^3+2^3+...+k^3+(k+1)^3)=(1+2+...+k+k+1)^2
(9+...+2k^3+3k^2+1)=(4+...+2k)^2
Right here I can see a problem, since the RHS will have a k^2 term, and the LHS will have k^3. Where did I go wrong? Are they supposed to be equal?
Thanks for any help.
 
Last edited:
Physics news on Phys.org
Do you know the expression Sum of i 1 to n is n*(n+1)/2 ? There's a pattern there. When you sqaure it, maybe you will find a k^3
 

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