Can kinetic energy be added linearly?

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SUMMARY

Kinetic energy cannot be added linearly due to the principles of special relativity. The discussion highlights that as velocity increases, an object's relativistic mass also increases, which affects kinetic energy calculations. The correct relativistic kinetic energy equation is K.E. = (\gamma - 1)mc², where γ (gamma) represents the Lorentz factor. This equation demonstrates that the increase in mass compensates for the non-linear increase in velocity, confirming that kinetic energy behaves differently than classical mechanics would suggest.

PREREQUISITES
  • Understanding of special relativity concepts
  • Familiarity with the Lorentz factor (γ)
  • Knowledge of kinetic energy equations in classical and relativistic contexts
  • Basic mathematical skills for manipulating equations
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  • Study the derivation of the Lorentz factor (γ) in special relativity
  • Explore the implications of relativistic mass on energy calculations
  • Learn about frame transformations in special relativity
  • Investigate the differences between classical and relativistic kinetic energy
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Students of physics, educators teaching special relativity, and anyone interested in the nuances of kinetic energy in relativistic contexts.

kbar1
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According to special relativity, velocity cannot be added to another velocity linearly. But I was thinking, what about kinetic energy? K.E. = mv2/2. As velocity increases, the object's mass also increases. The way I see it, the increase in mass "compensates" for the less-than-expected increase in velocity (as predicted by classical mechanics). So am I right in saying, kinetic energy can be added linearly?

Does what I said above agree with relativistic K.E. equation: K.E. = ([itex]\gamma[/itex]-1)mc2 ?
 
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kbar1 said:
The way I see it, the increase in mass "compensates" for the less-than-expected increase in velocity (as predicted by classical mechanics).

Have you actually checked the math?

kbar1 said:
Does what I said above agree with relativistic K.E. equation: K.E. = ([itex]\gamma[/itex]-1)mc2 ?

This is the correct equation; so have you checked to see what happens when you transform between frames?
 

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