Can Right-Handed Neutrinos Be Integrated into the Standard Model?

Click For Summary
SUMMARY

The discussion focuses on the integration of right-handed neutrinos into the Electroweak Standard Model, specifically referencing the expressions found in Mohapatra's "Massive Neutrinos in Physics and Astrophysics". The key expression under scrutiny is \overline{N^c_{l'L}}\nu^c_{lR}=\overline{\nu_{lL}}N_{l'R}, where N_{l'R} represents the right-handed field associated with right-handed neutrinos. The participants confirm that Majorana neutrinos, being their own antiparticles, allow the conjugate of the expression to remain unchanged, thus validating the equation.

PREREQUISITES
  • Understanding of Majorana neutrinos
  • Familiarity with the Electroweak Standard Model
  • Knowledge of particle physics notation and conjugation
  • Basic concepts of lepton flavor in particle physics
NEXT STEPS
  • Study Majorana neutrinos and their properties in depth
  • Explore the Electroweak Standard Model framework
  • Research conjugation in quantum field theory
  • Examine lepton flavor conservation and its implications
USEFUL FOR

Particle physicists, theoretical physicists, and students studying neutrino physics and the Standard Model will benefit from this discussion.

lalo_u
Gold Member
Messages
26
Reaction score
0
I am reading Mohapatra's book: "Massive Neutrinos in Physics and Astrophysics". At the beginning of chapter 7, it is sought expressions where the right neutrino was considered in the Electroweak Standard Model.
Everything was fine until I found the expression \overline{N^c_{l'L}}\nu^c_{lR}=\overline{\nu_{lL}}N_{l'R}.
Where N_{l'R} is the right handed field associated with right handed neutrinos and the subsctipts l,l' indicate the lepton flavors.

Well, I'm trying to prove this, but I get stuck on the following expression:

\overline{N^c_{l&#039;L}}\nu^c_{lR} =\overline{\left(N_{l&#039;L}\right)^c}\left(\nu_{lR}\right)^c<br /> = \overline{N_{l&#039;R}}\nu_{lL}
And I'm assuming that they are Majorana neutrinos.

To complete the test I should justify why the conjugate for the last expression can be taken and remain unchanged, someone could help?
 
Physics news on Phys.org
To prove the expression \overline{N^c_{l'L}}\nu^c_{lR}=\overline{\nu_{lL}}N_{l'R}, you can use the fact that Majorana particles are their own antiparticles. This means that the conjugate of a Majorana particle is equal to itself. Thus, taking the conjugate of the last expression will not change it: \overline{N_{l'R}}\nu_{lL} = \overline{\left(N_{l'R}\right)^c}\left(\nu_{lL}\right)^c = \overline{\nu_{lL}}N_{l'R}.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K