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Can someone answer this easy phsyics problem about vertical height

  1. Jan 2, 2012 #1
    1. The problem statement, all variables and given/known data


    A basketball player achieves a hang time of 0.978 s in dunking the ball.
    What vertical height will he attain? The
    acceleration of gravity is 9.8 m/s^2

    Answer in units of m


    2. Relevant equations
    ?
    3. The attempt at a solution 9.8/0.978^2= 10.245
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
    Last edited: Jan 2, 2012
  2. jcsd
  3. Jan 2, 2012 #2

    DaveC426913

    User Avatar
    Gold Member

    Yes. You can.

    We do not (can not) do homework for you. Show your work, we can help.
     
  4. Jan 2, 2012 #3
    The attempt at a solution 9.8/0.978^2= 10.245
     
  5. Jan 2, 2012 #4
    Remember that H=.5gt^2

    Retry and see what you get.
     
  6. Jan 2, 2012 #5
    I tried H=.5*g*t^2 and got 4.68677?
     
  7. Jan 2, 2012 #6
    22.9653?
     
  8. Jan 2, 2012 #7
    Remember that time going up = time coming down .
     
  9. Jan 2, 2012 #8
    No since t(up)=t(down)

    then: H=.5g*(t/2)^2
     
  10. Jan 2, 2012 #9
    what?
     
  11. Jan 2, 2012 #10
    Thanks a lot I got it but why is it half time^2?
     
  12. Jan 2, 2012 #11
    When you have the time going up = time going down, then you have: t(up)=t(down)=.978/2

    I'm helping you too much.
     
  13. Jan 2, 2012 #12
    I already got the the answer from the last response I was just wonder why it was half the time^2 if that was for every problem for this equation or just if an object is traveling up?
     
  14. Jan 2, 2012 #13
    Well since he is jumping upwards he only takes half of the time to get to his maximum height. Therefore the rest of the time is spent coming down. Hence no need for the time coming down.
     
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