Can someone check if this is correct please

[chelsea9947]

1. Given that the instruction

cmp.l d0,d1

subtracts d0 from d1 without changing either and then sets the flags accordingly.

What will be the state of the N and Z flags if

Homework Equations

a. d0 < d1 =
b. d0 > d1 =
c. d1 = d1 =

The Attempt at a Solution

a. is negative and N would be set.
b. the result is positive and neither N or Z is set.
c. the result is zero and Z would be set.

 

[CompuChip]

You mean: in each of the cases where d0 is smaller, equal or greater to d1, is d1 - d0 positive, negative or zero?

 

[chelsea9947]

i think is zero

Decision Making: In high level languages we use instructions of the form

If A< B then P else Q

Now what actually happens deep down in the machine is a subtraction of the form (A – B) and we look at the sign of the result.

If B is greater than A then the result is negative and N would be set.
If A is equal to B then the result is zero and Z would be set.
If A is greater than B the result is positive and neither N or Z is set.

Lots of combinations are possible e.g. “less than”, “less than or equal to”, “equal to each other”, “is something equal to, less than, or greater than zero” and so on.

 

[Mark44]

1. Given that the instruction

cmp.l d0,d1

subtracts d0 from d1 without changing either and then sets the flags accordingly.

What will be the state of the N and Z flags if

Homework Equations

a. d0 < d1 =
b. d0 > d1 =
c. d1 = d1 =

The Attempt at a Solution

a. is negative and N would be set.
b. the result is positive and neither N or Z is set.
c. the result is zero and Z would be set.

I don't believe you're thinking about this the right way. As you described it, the cmp d0, d1 instruction evaluates d1 - d0 and sets the N and Z flag, as appropriate. Obviously you aren't working with an x86-type processor, since it would evaluate d0 - d1.
a. If d0 < d1, then d1 - d0 > 0, so no flags get set.
b. If d0 > d1, then d1 - d0 < 0, so the N flag gets set.
c. I'm pretty sure you mean d0 = d1, since the value in d1 will always equal itself. When d0 = d1, the Z flag gets set.

 

[chelsea9947]

please can you check this if this is correct

cmpi.w #10,d5

What will the states of the N and Z flags would be if

a. d5 = 12 = No flags gets set.
b. d5 = -10 = Z flag gets set.
c. d5 = 5 = N would be set

 

[Mark44]

please can you check this if this is correct

cmpi.w #10,d5

What will the states of the N and Z flags would be if

a. d5 = 12 = No flags gets set.
b. d5 = -10 = Z flag gets set.
c. d5 = 5 = N would be set

a. correct
b. The N flag gets set, not the Z flag. The subtraction that is performed is -10 - 10, which is -20.
c. correct