Can someone double check my work in this problem?

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SUMMARY

The forum discussion centers on the complete factoring of two expressions: 2e^(3x) - 5xe^(3x) and 4ln(x) - 3yln(x). The user correctly factored the first expression as e^(3x)(2 - 5x) and the second as ln(x)(4 - 3y). However, it was advised to use parentheses for clarity, specifically e^(3x) and (4 - 3y)ln(x), to avoid misunderstandings regarding the logarithmic function.

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Homework Statement



Okay, I think these are simple, but just so I know that I am on the right track, can you double check my work? My questions and answers are in bold.

Factor these completely:

1. 2e^3x - 5xe^3x

2. 4lnx -3ylnx


3. The Attempt at a Solution

1. I took out the e^3x to make the factored problem e^3x(2-5x)Did I do that right, because I get confused when dealing with the exponents. If there is more to it, can you explain please? Thanks in advance.

2. I just took out the lnx to make it lnx(4-3y) . Is this correct?
 
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name_ask17 said:

Homework Statement



Okay, I think these are simple, but just so I know that I am on the right track, can you double check my work? My questions and answers are in bold.

Factor these completely:

1. 2e^3x - 5xe^3x

2. 4lnx -3ylnx


3. The Attempt at a Solution

1. I took out the e^3x to make the factored problem e^3x(2-5x)Did I do that right, because I get confused when dealing with the exponents. If there is more to it, can you explain please? Thanks in advance.

2. I just took out the lnx to make it lnx(4-3y) . Is this correct?

They are both correct but you need parentheses. For example e^(3x). Also, while not incorrect, it is better to write the last one (4-3y)ln(x) to remove any possible misunderstanding about what is inside the ln function.
 
Thanks! Just wanted to make sure they were correct because it seemed too simple. Guess I'm used to overthinking things. lol.
 

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