- #1

- 91

- 0

(Ldv)/(AgL+v^2) from [v0,0]

I'm supposed to get (...)arctan(...)

where (...) are 2 different quantities.

I'm confused on how to get arctan out of this integral when

arctan = integral of

(1*dv)/(1+v^2) from [0,x]

Help is appreciated.

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- Thread starter btbam91
- Start date

- #1

- 91

- 0

(Ldv)/(AgL+v^2) from [v0,0]

I'm supposed to get (...)arctan(...)

where (...) are 2 different quantities.

I'm confused on how to get arctan out of this integral when

arctan = integral of

(1*dv)/(1+v^2) from [0,x]

Help is appreciated.

- #2

tiny-tim

Science Advisor

Homework Helper

- 25,832

- 251

(try using the X

scale it down … substitute v = x√(AgL)

(or go straight to v = √(AgL)tanθ)

- #3

HallsofIvy

Science Advisor

Homework Helper

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[tex]\frac{ L dv}{AgL+ v^2}[/tex]

by AgL:

[tex]\frac{\frac{1}{Ag}dv}{1+ \frac{v^2}{AgL}}[/tex]

and then make the substitution

[tex]u= \frac{v}{\sqrt{AgL}}[/tex]

Because [itex]du= dv/\sqrt{AgL}[/itex] that changes the integral to

[tex]\sqrt{\frac{L}{Ag}}\int \frac{du}{1+ u^2}[/tex]

- #4

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- 0

Thanks guys! I really appreciate it!

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