Can someone help me to identify the formula on the attached image?

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Homework Help Overview

The discussion revolves around identifying a formula related to heat diffusion, specifically in the context of a MATLAB assignment. The original poster is uncertain whether the formula is the Laplace equation or the 2D Heat Diffusion equation.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the nature of the equation, with some asserting it is the heat equation and exploring the implications of multiplying by a constant. Questions arise regarding the presence of 1/alpha in the equation and its equivalence to the standard form.

Discussion Status

There is ongoing exploration of the formula's identity, with some participants providing guidance on its classification as the heat equation. Multiple interpretations of the equation's form are being discussed, particularly regarding the role of alpha.

Contextual Notes

Participants note that problems involving derivatives should be posted in appropriate sections, indicating a potential misunderstanding of the problem's classification.

t0mm02
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Homework Statement
2D diffusion equation model using the Explicit Finite Difference Method
Relevant Equations
Lapace Equation, 2D Diffusion Equation
I have to do a MATLAB assignment but when it comes to the report (the theory) I am having quite a lot of problems. My tutor used this formula that I am going to attach:
139785274_10221322680269558_4797605297380943788_n.jpg


However, I don't know if that equation is the Laplace equation, the 2D Heat Diffusion equation, or what exactly that is as I can not find it anywhere like he wrote it on there.
 
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That's the heat equation. Multiplying both sides by \alpha gives the standard form <br /> \frac{\partial T}{\partial t} = \alpha\left(\frac{\partial^2 T}{\partial x^2} + <br /> \frac{\partial^2 T}{\partial y^2}\right)
 
pasmith said:
That's the heat equation. Multiplying both sides by \alpha gives the standard form <br /> \frac{\partial T}{\partial t} = \alpha\left(\frac{\partial^2 T}{\partial x^2} +<br /> \frac{\partial^2 T}{\partial y^2}\right)
If it was only alpha in stead of 1/alpha I would understand it. Why is it 1/alpha?
 
t0mm02 said:
If it was only alpha in stead of 1/alpha I would understand it. Why is it 1/alpha?
What is it you don't understand? These two equations are equivalent.
$$\frac{\partial T}{\partial t} = \alpha\left(\frac{\partial^2 T}{\partial x^2} +
\frac{\partial^2 T}{\partial y^2}\right)$$
$$\frac 1 \alpha\frac{\partial T}{\partial t} =\frac{\partial^2 T}{\partial x^2} +
\frac{\partial^2 T}{\partial y^2}$$

By the way, problems involving derivatives or partial derivatives are NOT precalculus. Please post any such problems in the Calculus & Beyond homework section or in one of the Physics homework sections.
 

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