How Do You Calculate the Launch Velocity Components in a Football Field Goal?

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SUMMARY

The discussion focuses on calculating the launch velocity components for a football field goal and a rocket's trajectory. The kicker's ball experiences an acceleration of 229 m/s² for 0.0300 seconds, resulting in horizontal (Ax) and vertical (Ay) components of 146.28 m/s and 176.19 m/s, respectively. Additionally, the rocket is launched at 63.0 m/s at a 37.0° angle, achieving horizontal (Vox) and vertical (Voy) components of 50.31 m/s and 37.91 m/s. The calculations for both scenarios demonstrate the application of kinematic equations to determine projectile motion.

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  • Understanding of kinematic equations in physics
  • Knowledge of vector decomposition for velocity components
  • Familiarity with projectile motion concepts
  • Basic proficiency in trigonometry for angle calculations
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of projectile motion and velocity calculations in sports and engineering contexts.

Miss1nik2
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Can someone PLEASE help me with this problem??

In a football game a kicker attempts a field goal. The ball remains in contact with the kicker's foot for 0.0300 s, during which time it experiences an acceleration of 229 m/s2. The ball is launched at an angle of 50.3 ° above the ground. Determine the (a) horizontal and (b) vertical components of the launch velocity.

I figured out that Ax=146.28 and Ay= 176.19, but I am stuck after that.
 
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well you did the hard part...

I would've found the velocity first then broken it down into components, but I suppose your way is just as good...

you got t = .03 s
you got Ax = 146.28 and Ay = 176.19

well, Velocity = (acceleration) X (time)

so find Vx and Vy
 


I think I got it. Thanks.

But now I need help with...

A rocket is fired at a speed of 63.0 m/s from ground level, at an angle of 37.0 ° above the horizontal. The rocket is fired toward an 18.1-m high wall, which is located 32.0 m away. The rocket attains its launch speed in a negligibly short period of time, after which its engines shut down and the rocket coasts. By how much does the rocket clear the top of the wall?

I got Vox=50.31 and Voy=37.91. And I got, at 32 m the time is t=.64s. Then y=22.26. Then subtract 18.1 and I got 4.16.
 


...well in that case I don't think u need help at all, because I got the same answer! good job!
 

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