Can someone tell me how they did cross product?

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SUMMARY

The discussion focuses on the calculation of angular momentum as the cross product of the position vector \( \vec{r} \) and the momentum \( m\vec{v} \). It clarifies that the scalar quantities \( m \), \( v \), and \( R \) are multiplied directly and kept outside the parentheses, while the vector components are handled within the cross product. The second parentheses should represent angular velocity \( \omega \) instead of the velocity \( v \). The cross product is established as bilinear, allowing for the distribution of scalar multiplication across vector operations.

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Warlic
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Homework Statement


upload_2015-11-7_21-57-44.png


Angular momentum is the cross product of r and mv. But why is there mvR outside of the paranthesis? And where did the v go in the second paranthesis - shouldn't the second paranthesis be (-v*sin(ωt), v* cos(ωt)). Does anyone have any idea how they did the cross product, because I'm totally lost.

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The Attempt at a Solution

 
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Go through how vector cross products are done :
https://en.wikipedia.org/wiki/Cross_product

Also, m,v, R - all being scalar ( just numbers, see they are without arrows) are multiplied dierctly and so kept outside while the main (vector) components of cross product is kept within the third bracket.

Second paranthesis, v/R is replaced by angular velocity "ω".

See the link for the process.
 
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The cross product is bilinear. That means that for all vectors ##\vec x,\vec y,\vec z## and all numbers ##a,b##, we have
$$(a\vec x+b\vec y)\times \vec z =a(\vec x\times\vec z) +b(\vec y\times\vec z)$$ and
$$\vec x\times (a\vec y+b\vec z)=a(\vec x\times y)+b(\vec x\times\vec z).$$
 
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