How Is Angular Momentum Calculated in Particle Motion?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the angular momentum of a particle moving in the xy plane, given its mass, velocity, and position vector. Participants are examining the application of the angular momentum formula and the implications of directionality in their calculations.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants describe the process of calculating momentum and taking the cross product to find angular momentum. Questions arise regarding the correctness of the computed magnitude and the significance of direction in angular momentum.

Discussion Status

Some participants have provided guidance on the nature of magnitudes, noting that they cannot be negative. The conversation reflects a mix of attempts to clarify the calculations and explore the implications of the results, though no consensus has been reached on the correct approach.

Contextual Notes

Participants are working under the constraints of a homework assignment, which specifies the need to determine only the magnitude of angular momentum. There is an ongoing exploration of assumptions related to the directionality of angular momentum as a pseudo-vector.

thehiggsboson
Messages
4
Reaction score
0

Homework Statement



A 1.47kg particle moves in the xy plane with a velocity of v = (4.59i - 3.28j)m/s. Determine the magnitude of the particle's angular momentum when its position vector is r = (1.35i + 2.57j)m.


Homework Equations



p = mv

L = r x p (the x is supposed to be a cross product and not a variable)

L = r x mv

The Attempt at a Solution



First I scaled the velocity vector: v = (4.59i - 3.28j)m/s by the mass, 1.47 kg, to get a new momentum vector (6.75i - 4.82j)kg*m/s.

Then I took the cross product of the r vector with the new momentum vector:
(1.35i + 2.57j)m x (6.75i - 4.82j)kg*m/s (I let a=1.35, b=2.57, c=0, d=6.75, e=-4.82, and f=0, the got the k vector cross product by doing k=ae-bd)

The answer I got was -23.9 kg*m^2/s, which wasn't right.

What did I do wrong? Am I even anywhere near the correct solution/answer?
 
Last edited:
Physics news on Phys.org
thehiggsboson said:

Homework Statement



A 1.47kg particle moves in the xy plane with a velocity of v = (4.59i - 3.28j)m/s. Determine the magnitude of the particle's angular momentum when its position vector is r = (1.35i + 2.57j)m.


Homework Equations



p = mv

L = r x p (the x is supposed to be a cross product and not a variable)

L = r x mv

The Attempt at a Solution



First I scaled the velocity vector: v = (4.59i - 3.28j)m/s by the mass, 1.47 kg, to get a new momentum vector (6.75i - 4.82j)kg*m/s.

Then I took the cross product of the r vector with the new momentum vector:
(1.35i + 2.57j)m x (6.75i - 4.82j)kg*m/s (I let a=1.35, b=2.57, c=0, d=6.75, e=-4.82, and f=0, the got the k vector cross product by doing k=ae-bd)

The answer I got was -23.9 kg*m^2/s, which wasn't right.

What did I do wrong? Am I even anywhere near the correct solution/answer?

Did you specify the direction of the angular momentum? (It's a pseudo-vector, so it has a magnitude and direction).
 
I didn't, but I just went back and tried it and it picked up the k as being part of the unit. So, it's not that, I don't think. The question also just asks for magnitude.
 
thehiggsboson said:
I didn't, but I just went back and tried it and it picked up the k as being part of the unit. So, it's not that, I don't think. The question also just asks for magnitude.
Okay, just the magnitude. What answer did you type in for that?
 
-23.9 kg*m^2/s
 
Are magnitudes ever negative?
 
Nope. Wow, I feel a little stupid now. Thanks!
 
thehiggsboson said:
Nope. Wow, I feel a little stupid now. Thanks!

Heh. We've all been there, done that, got the T-shirt. Cheers.
 

Similar threads

Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
6K
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K