- #1
Planobilly
- 440
- 105
I read this statement from Lenard Audio.
"When a large signal spike is created by un-plugging or plugging in signal leads, or when a pre-amp valve is driven hard into distortion (guitar amps), a large non-symmetrical square wave may cause a temporary DC Voltage to appear across a coupling capacitor, to the Grid of the following valve. This short DC pulse will cause the following valve to be shut off, or go into full conduction, for approx 1mS to 1 second, until the following Grid resistor discharges the coupling capicator."
First, is this statement correct. Second, if yes, how does this work?
Thanks,
Billy
"When a large signal spike is created by un-plugging or plugging in signal leads, or when a pre-amp valve is driven hard into distortion (guitar amps), a large non-symmetrical square wave may cause a temporary DC Voltage to appear across a coupling capacitor, to the Grid of the following valve. This short DC pulse will cause the following valve to be shut off, or go into full conduction, for approx 1mS to 1 second, until the following Grid resistor discharges the coupling capicator."
First, is this statement correct. Second, if yes, how does this work?
Thanks,
Billy