Can the Integral of (1+x^3) be Bounded Between 2 and 6?

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SUMMARY

The integral of the function (1+x^3) over the interval [0,2] can be conclusively bounded between 2 and 6. This conclusion is derived from the application of the bounding theorem, which states that if a function is constrained by two constants, the integral of that function will also be constrained by the integrals of those constants. By graphing the function within the specified range, one can visually confirm that the area under the curve lies between these two bounds.

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  • Knowledge of area under curves
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  • Learn about bounding theorems and their applications
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Homework Statement



Prove without computation that 2<Integral[0,2] (1+x^3)<6


The Attempt at a Solution



I know there is a theorem which says that if a function is bounded by two constants, then the integral of the function is also bounded by the integrals of the two functions. However, I'm not sure if that would apply. So how should I approach this one without computation? Thanks
 
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Here is a hint: the integral gives an area. Draw the graph in the given range.
 

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