Can the product of two integrals be simplified into one using dummy variables?

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SUMMARY

The discussion centers on the simplification of the product of two integrals involving dummy variables. Specifically, the integral A is defined as A = ∫ (d^d p)/(2π)^d Z[p]. The question arises whether A* A can be expressed as ∫ (d^d p)/(2π)^d Z*[p] Z[p]. The consensus is that while the integrals can be manipulated using dummy variables, the simplification into a single integral depends on the specific form of Z. An example using Mathematica demonstrates that this simplification does not hold universally.

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Hepth
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If I have an integral:
[tex]A = \int \frac{d^d p}{(2 \pi)^d} Z[p][/tex]

And I want [tex]A^* A[/tex]

Is it
[tex]A^* A = \int \frac{d^d p}{(2 \pi)^d} Z^*[p] Z[p][/tex] ?

Because the "p" is the same, and really it would be integral 1 times integral 2 times a delta, which should make it just one.

I don't think its true, and an example in mathematica doesn't work.

Is there a shortcut to get the product of two integrals to be one?:
[tex](\int \frac{d^d p}{(2 \pi)^d} Z^*[p])( \int \frac{d^d p}{(2 \pi)^d} Z[p]) =[/tex]

hmm, the product of two sums...
 
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Recall that the variables you integrate over are dummy variables. So you should write
[tex](\int \frac{d^d q}{(2 \pi)^d} Z^*[q])( \int \frac{d^d p}{(2 \pi)^d} Z[p]) =<br /> \int \frac{d^d q}{(2 \pi)^d} \int \frac{d^d p}{(2 \pi)^d} Z^*[q] Z[p][/tex].

Whether or not you can do something clever with this to make it a single integral depends on the form of [tex]Z[/tex].
 

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