Can These Points Form a Square in Geometric Constructions?

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SUMMARY

The discussion centers on proving that points P, Q, R, and S form the vertices of a square in a geometric construction involving squares ABDE and BCGH outside triangle ABC. The centers of these squares are defined as P and Q, while R and S are the midpoints of segments AC and DH, respectively. A key hint provided is to demonstrate that the distances P-S and R-Q are equal and that P-S equals the imaginary unit multiplied by the vector R-P, establishing the geometric relationship necessary for the points to form a square.

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let ABDE and BCGH be squares lying outside the traingle ABC. The centres of these sqaures are P & Q respecitvely, and the midpoints of the line segments AC and DH are R & S respectively. Show that the points P,Q,R,S are vertices of a square?

any ideas on how to do this please?

the only hint i have is to show that P-S = R-Q = i(R -P) where i = imaginary..
 
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Er... this is homework, correct? FYI, somewhere around PF we have a special place with special rules for homework help.

Here's a hint: if you have an equation like [itex]z = i \, w[/itex], you know that [itex]z, w[/itex] are complex numbers, yes? But you know that these can be thought of as vectors, right? So what does [itex]z = i \, w[/itex] mean geometrically?
 

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