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Regualr hexagon and position vector - how does this work

  1. Jul 19, 2012 #1
    1. The problem statement, all variables and given/known data
    a regular hexagon OPQRST has its vertices at O ( the origin) and points P,Q,R, S,T with position vector p,q,r,s,t respectively. The point U with position vector u is the midpoint of the line segment OP, and SU meets OR at the point V
    please see attached diagem


    I need to show that the position vector r=2(p+t) and write down the position vector u and s, in terms of p and t.

    Now what I do know is I have marked on my diagram in colour - however I am not sure any further as this is very new to me. so your help will be appreciated.
     
    Last edited: Jul 20, 2012
  2. jcsd
  3. Jul 19, 2012 #2

    LCKurtz

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    At the moment you have had 73 viewers and 2 of them looked at your word document. Many of us, myself included, will not open a Word document off the internet. You will have more luck if you post a simple graphic so we can see it when we read your post.
     
  4. Jul 20, 2012 #3
    Ok. Will do.
     
  5. Jul 20, 2012 #4
    here I am attaching bitmap so jope someone can help.. word doc is problem so I will remove it
     

    Attached Files:

  6. Jul 20, 2012 #5

    LCKurtz

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    Here's a start: ##r = p + PQ +QR##. Can you show from the geometry of the regular hexagon that ##QR = t## and ##PQ = p + t##? That should get you your equation for ##r##.
     
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