Regualr hexagon and position vector - how does this work

[rohan03]

Homework Statement

a regular hexagon OPQRST has its vertices at O ( the origin) and points P,Q,R, S,T with position vector p,q,r,s,t respectively. The point U with position vector u is the midpoint of the line segment OP, and SU meets OR at the point V
please see attached diagem


I need to show that the position vector r=2(p+t) and write down the position vector u and s, in terms of p and t.

Now what I do know is I have marked on my diagram in colour - however I am not sure any further as this is very new to me. so your help will be appreciated.

 

[LCKurtz]

At the moment you have had 73 viewers and 2 of them looked at your word document. Many of us, myself included, will not open a Word document off the internet. You will have more luck if you post a simple graphic so we can see it when we read your post.

 

[rohan03]

Ok. Will do.

 

[rohan03]

here I am attaching bitmap so jope someone can help.. word doc is problem so I will remove it

 

[LCKurtz]

Here's a start: $r = p + PQ +QR$. Can you show from the geometry of the regular hexagon that $QR = t$ and $PQ = p + t$? That should get you your equation for $r$.