Can We Reach Speed of Light w/ Model?

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Discussion Overview

The discussion revolves around the feasibility of reaching the speed of light using a rotating disk model. Participants explore the implications of such a model within the context of relativistic physics and geometry.

Discussion Character

  • Debate/contested, Conceptual clarification, Technical explanation

Main Points Raised

  • One participant proposes a scenario involving a large disk rotating at a specified speed and questions whether the speed at the disk's boundary could reach 30,000 km/s.
  • Another participant directly challenges the initial claim, indicating that the proposed speed is incorrect.
  • A third participant suggests reviewing a related discussion that addresses similar concepts regarding relativistic speeds and geometrical implications.
  • Another comment highlights the limitations of applying Euclidean geometry in the context of relativity, implying that traditional geometric principles may not hold in this scenario.

Areas of Agreement / Disagreement

Participants exhibit disagreement regarding the initial claim about the speed of the disk's boundary, with at least one participant asserting that the calculation is incorrect. The discussion remains unresolved as to the implications of the rotating disk model in relation to relativistic physics.

Contextual Notes

There are limitations in the assumptions made about the applicability of classical mechanics to relativistic scenarios, as well as potential dependencies on the definitions of speed and geometry in relativistic contexts.

ztdep
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Dear friends:
Put a big disk in the space which can rotate at a speed. for example, if the radius of the disk is 10000km, and it rotates at a speed of 30 rad/s, then the speed at the disk boundary is 30,0000km/s.
am i right?
 
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ztdep said:
Dear friends:
Put a big disk in the space which can rotate at a speed. for example, if the radius of the disk is 10000km, and it rotates at a speed of 30 rad/s, then the speed at the disk boundary is 30,0000km/s.
am i right?
No.

 
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Likes   Reactions: Imager
This is one reason why Euclidean geometry doesn't apply in relativity.
 

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