Can we simply truncate a Fourier series if it is divergent?

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SUMMARY

Truncating a divergent Fourier series, such as the series defined by \(\sum_{n=0}^{\infty}\frac{cos(nx)}{\sqrt{n}}\), is mathematically permissible to obtain finite results. However, the truncated series does not converge to a meaningful limit as \(N\) increases. The underlying issue revolves around the representation of the series, particularly regarding its energy, which is calculated as \(\sum (1/n)\) and is infinite. Thus, while truncation yields finite outputs, the significance of these results remains questionable.

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can we simply truncate a Fourier series if it is divergent??

given a Fourier series of the form

\sum_{n=0}^{\infty}\frac{cos(nx)}{\sqrt{n}}

can i simply truncate this series up to some number finite N so i can get finite results ?? thanks.
 
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You can always truncate the series to get a finite result. However the result as a function of N does not converge to anything.
 


Maybe a more fundamental question is "what is your series supposed to represent?" For eaxmple, the energy (measured as the function squared) is ##\sum (1/n)## which is infinite.

As mathman said, you can do anything you like mathematically with a finite number of terms, but whether the result means anything is another question.
 

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