Can You Calculate Tension and Earth's Angular Attributes?

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SUMMARY

The discussion focuses on calculating tension in a string and Earth's angular attributes. For Q1, the tension in the string at the highest and lowest points can be determined using centripetal acceleration formulas, given a string length of 1.0m and a mass of 0.5kg with an angular speed of 3 revolutions per second. For Q2, participants are tasked with calculating the Earth's angular speed, energy, torque, and average power required to accelerate the Earth from rest to its current angular speed, using the mass of the Earth (6 x 1024 kg) and its radius (6400 km).

PREREQUISITES
  • Centripetal acceleration concepts
  • Angular speed calculations
  • Energy and torque formulas
  • Basic physics of rotational motion
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  • Study centripetal acceleration and its relation to tension in strings
  • Learn how to calculate angular speed using Earth's parameters
  • Explore energy and torque calculations in rotational dynamics
  • Investigate average power calculations in physics
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Physics students, educators, and anyone interested in understanding the dynamics of rotational motion and the calculations involved in tension and angular attributes of celestial bodies.

iloveuok
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Hi Guys,

I face some problems answering below questions. Anyone can help to answer?

Q1: One end of a string of length 1.0m is tied to body of mass 0.5kg. It is whirled in a vertical circle. If its angular speed is 3rev/s, calculate the tension in the string at the highest and lowest points.

Q2: (a) Calculate the angular speed of the earth.
(b) Calculate the
(i) Energy
(ii) Torque and (iii) average power
required to accelerate the Earth in 1 day from rest to its present angular speed.
(Mass of the Earth : 6x10 power 24 kg , radius of erath = 6400km)

Thanks.

Regards,
Alex
 
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We cannot just give you the answers, that's against the PF Guidelines. Please show us what you have done so far.

regards
marlon

ps : as a hint to Q1. Can you link the orbital velocity to an acceleration (centripetal) ? There is a nice and easy formula for this. If you do this, you are on your way...
 
Last edited:

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