Can you charge a battery with another battery?

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SUMMARY

Charging a battery directly with another battery is not advisable due to safety concerns, including the risk of explosions. Instead, battery-based chargers utilize specialized circuitry to ensure a safe and efficient charging process. Capacitors can charge each other, but energy is lost during this transfer. When charging a capacitor with batteries of different voltages, the final voltage depends on the capacitor's capacitance and the initial charge levels.

PREREQUISITES
  • Understanding of battery chemistry and charging principles
  • Knowledge of capacitor behavior and charge conservation
  • Familiarity with electrical circuits and components
  • Basic concepts of resistance and inductance in circuits
NEXT STEPS
  • Research battery charger circuitry design for safe charging
  • Learn about capacitor discharge and voltage calculations
  • Explore the effects of resistance and inductance in RC circuits
  • Investigate the "zapping" process for NiCad cells and its implications
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Electronics enthusiasts, electrical engineers, and anyone involved in battery technology or capacitor applications will benefit from this discussion.

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To do this would you simply run the current from one battery through another in reverse? Would there be a significant loss in energy?
 
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It is not impossible in general, but it can lead to bad consequences (including exploding batteries) if done improperly. Just don't do it.
 
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radaballer said:
To do this would you simply run the current from one battery through another in reverse? Would there be a significant loss in energy?

As mfb says, not directly. But there are battery-based battery chargers that have circuitry inside that makes the charging process safe and relatively efficient:

http://www.schoolmart.com/images/products/detail/EVOPowerPlusintocell.jpg
http://www.schoolmart.com/images/products/detail/EVOPowerPlusintocell.jpg
 
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berkeman said:
As mfb says, not directly. But there are battery-based battery chargers that have circuitry inside that makes the charging process safe and relatively efficient:

http://www.schoolmart.com/images/products/detail/EVOPowerPlusintocell.jpg
http://www.schoolmart.com/images/products/detail/EVOPowerPlusintocell.jpg
Ok, what about a capacitor charging a capacitor? And would charge be lost?
 
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radaballer said:
Ok, what about a capacitor charging a capacitor? And would charge be lost?

Charge is conserved, but some energy is lost in the transfer of charge from one capacitor to another. In fact, it is a common FAQ to figure out where the energy goes... :smile:
 
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berkeman said:
Charge is conserved, but some energy is lost in the transfer of charge from one capacitor to another. In fact, it is a common FAQ to figure out where the energy goes... :smile:
Ok lastly, what happens if you add two different quantities of charge with different voltages to a single capacitor? How would they come out in the discharge of the capacitor?
 
radaballer said:
Ok lastly, what happens if you add two different quantities of charge with different voltages to a single capacitor?
That question does not make sense. You cannot "add a charge of X at voltage Y", the voltage is determined by the amount of charge and the capacitance (and it changes during the charging process).
 
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mfb said:
That question does not make sense.
sorry, If i charge a capacitor with a 12 volt battery for 30 seconds, then I charge it with a 9 volt battery for 30 seconds, what voltage will come back out of the capacitor? Hope that makes more sense.
 
radaballer said:
what voltage will come back out of the capacitor?
It might be more relevant to ask how much smoke will come out of the battery.
 
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radaballer said:
sorry, If i charge a capacitor with a 12 volt battery for 30 seconds, then I charge it with a 9 volt battery for 30 seconds, what voltage will come back out of the capacitor? Hope that makes more sense.

That depends on several factors, including the capacitance of the capacitor. If the capacitance is too small, then the capacitor is completely charged to 12 volts and connecting a 9-volt battery to it will probably damage the battery. If its very large then the 12v battery will not charge it to even 9 volts and you can then connect the 9v battery and charge it to 9v.

See here for more info: http://www.electronics-tutorials.ws/rc/rc_1.html
 
  • #11
berkeman said:
Charge is conserved, but some energy is lost in the transfer of charge from one capacitor to another. In fact, it is a common FAQ to figure out where the energy goes... :smile:
Do we know where the energy goes?
 
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radaballer said:
Do we know where the energy goes?

Yes we do. :smile:
 
  • #13
radaballer said:
To do this would you simply run the current from one battery through another in reverse? Would there be a significant loss in energy?
You need higher potential to charge a battery. So if you are charging a 12V battery you would need 13-14V of any current throughput to charge that 12V bat.
 
  • #14
There's some resistance and inductance in the circuit which can't be ignored when dealing with capacitors. If the inductance is negligible, then the RC product determines the charging or discharging time. With inductance, you can get damped oscillations.
 
  • #15
berkeman said:
Yes we do. :smile:
Is there a way to calculate the energy lost through oscillations? If so can you show me or direct me to a link? Thanks for the help sir
 
  • #16
MrAnchovy said:
It might be more relevant to ask how much smoke will come out of the battery.

Some years ago it was discovered that certain sub C size NiCad cells performed better in RC cars and competition aircraft after they had been "zapped". The zapping process involved charging up a bank of capacitors the size of a shoebox and discharging them into the cell using an SCR the size of a hockey puck (I heard early experiments involved using a garden spade as a switch!). The wires connecting the capacitors to the cells would twitch due to the high current and Earth's magnetic field. A very high percentage of the cells survived.

Do not try this at home! It's very dangerous.
 

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