Can You Solve the Radial Diffusion Equation with Given Conditions?

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SUMMARY

The discussion centers around solving the radial diffusion equation represented as dM/dt = D.[d²M/dr² + (2/r)(dM/dr)] - k.M, with specified initial and boundary conditions: at t=0, M=Mo; at r=0, dM/dr=0; and at r=R, M=Ms. Participants emphasize the importance of individual effort in problem-solving and discourage direct provision of complete solutions. The focus is on guiding users to understand the methodology rather than simply providing answers.

PREREQUISITES
  • Understanding of differential equations, specifically partial differential equations.
  • Familiarity with boundary value problems and initial conditions.
  • Knowledge of diffusion processes in mathematical modeling.
  • Proficiency in mathematical software tools for numerical solutions, such as MATLAB or Python.
NEXT STEPS
  • Study the method of separation of variables for solving partial differential equations.
  • Learn about numerical methods for boundary value problems, focusing on finite difference methods.
  • Explore MATLAB's PDE toolbox for simulating diffusion equations.
  • Investigate the physical implications of the parameters D and k in diffusion processes.
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Mathematicians, physicists, and engineering students who are tackling diffusion equations and seeking to deepen their understanding of mathematical modeling and numerical analysis.

ayildirim10
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dear Hils0005

I have an equation as:

dM/dt=D.[d^2M/dr^2 +(2/r)(dM/dr)]-k.M

and initial and boundary conditions are:
t=0, M=Mo
r=0, dM/dr=0
r=R, M=Ms


Would you solve this equation, please?
your simcerely...
 
Last edited:
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ayildirim10 said:
dear Hils0005

I have an equation as:

dM/dt=D.[d^2M/dr^2 +(2/r)(dM/dr)]-k.M

and initial and boundary conditions are:
t=0, M=Mo
r=0, dM/dr=0
r=R, M=Ms


Would you solve this equation, please?
your simcerely...
Hello ayildirim10,

We will not provide you with complete solutions here. We will not do your homework for you, nor will we permit others to do it for you.

We are more than happy to help you solve your problems, but you have to do the work!
 

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