Can you think of a counter example (real analysis)

Click For Summary

Homework Help Overview

The discussion revolves around the properties of closed sets in real analysis, specifically focusing on the sum of two closed non-empty subsets of real numbers, X and Y. The original poster seeks a counterexample where the sum set X+Y is not closed.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore various examples of closed sets and their sums, questioning the conditions under which X+Y might not be closed. There are attempts to clarify the definition of X+Y and the implications of "deleting" points from the set.

Discussion Status

The conversation is ongoing, with participants providing hints and suggestions while expressing confusion about certain aspects of the problem. Some participants are considering the role of isolated points and the potential for creating limit points through manipulation of the sets.

Contextual Notes

There is a mention of constraints regarding finite subsets being closed and the challenge of finding examples that meet the criteria of the problem. Participants are also grappling with the concept of "deleting" points from the sum set.

robertdeniro
Messages
37
Reaction score
0

Homework Statement


X and Y are two closed non-empty subsets of R (real numbers).

define X+Y to be (x+y | x belongs to X and y belongs to Y)

give an example where X+Y is not closed

Homework Equations


The Attempt at a Solution


i tried X=all integers and Y=[0 1] but that didnt work out.
i know X+Y must be non-finite because all finite subsets are closed.
 
Physics news on Phys.org
Well you simply want to define X+Y such that some points are deleted.:-)
 
╔(σ_σ)╝ said:
Well you simply want to define X+Y such that some points are deleted.:-)

ya i was thinking of that too. haven't found a way yet? can you give 1 more hint?
 
Well define one point in X to be negative the other point in Y.
 
╔(σ_σ)╝ said:
Well define one point in X to be negative the other point in Y.

hmm just to make sure you didnt misunderstand the definition of X+Y

if X=[1 3] and Y={-2}

then X+Y = [-1 1]

so I am still confused by your suggestion
 
My suggestion is a bit vague and not helpful but think about if it is possible to delete stuff from X+Y.
 
Think about isolated points. Sets all of whose points are isolated are closed, but by manipulating them, you may be able to produce a limit point in a convenient place.
 
thanks for all the tips, I am going to think about this, hopefully ill discover it soon
 
i still haven't figure this out yet...but i was wondering if the solution has a "hole" in an interval?

and I am still confused about the "deleting" suggestion. since a negative and a positive would only produce zero and not remove the element from the set. in essence, you can only stretch and shift an interval.
 
  • #10
robertdeniro said:
i still haven't figure this out yet...but i was wondering if the solution has a "hole" in an interval?

and I am still confused about the "deleting" suggestion. since a negative and a positive would only produce zero and not remove the element from the set. in essence, you can only stretch and shift an interval.

Take r to be irrational. Did you know you can find whole multiples of r that are arbitrarily close to being integers?
 
  • #11
i think if X=the integers and Y=sqrt(2) * the integers then it would work.

i still can't think of an example where points are deleted.
 
  • #12
robertdeniro said:
i think if X=the integers and Y=sqrt(2) * the integers then it would work.

i still can't think of an example where points are deleted.

If you think the first example will work can you show it does? I wouldn't worry about the 'points deleted' example. It's not at all clear to me what that's supposed to mean.
 

Similar threads

Replies
15
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 4 ·
Replies
4
Views
14K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K