1. The problem statement, all variables and given/known data (a) Determine the capacitance of a Teflon-filled parallel-plate capacitor having a plate area of 1.90 cm2 and insulation thickness of 0.0600 mm. (b) Determine the maximum potential difference that can be applied to the capacitor. kV 2. Relevant equations I THOUGHT C = [tex]\epsilon[/tex]0*A all divided by d 3. The attempt at a solution I did 8.85x10^-12 * 1.90 / .06x10^-3 it came up wrong. I have to answer in pF btw. I also have no idea how to answer part b since I cant get part a correct. Can anyone give me the equation for part b as well? Thank you so much PhysicsForums!