(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

(a) Determine the capacitance of a Teflon-filled parallel-plate capacitor having a plate area of 1.90 cm2 and insulation thickness of 0.0600 mm.

(b) Determine the maximum potential difference that can be applied to the capacitor.

kV

2. Relevant equations

I THOUGHT C = [tex]\epsilon[/tex]0*A all divided by d

3. The attempt at a solution

I did 8.85x10^-12 * 1.90 / .06x10^-3

it came up wrong.

I have to answer in pF btw.

I also have no idea how to answer part b since I cant get part a correct. Can anyone give me the equation for part b as well?

Thank you so much PhysicsForums!

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# Homework Help: Capacitance and Max Potential Difference

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