- #1

MathewsMD

- 433

- 7

**Capacitance -- combining multiple capacitors for equivalent C**

In the given problem, C

_{eq}= C

_{1}C

_{2}C

_{3}C

_{4}/(C

_{1}+ C

_{2}+ C

_{3}+ C

_{4})

The answer says the equivalent capacitance is always less than C

_{1}but I can't come up with thy. When I do this, I can't seem to prove that equivalent capacitance is always less than C

_{1}. For example, if I let:

C

_{1}= 998 F, C

_{2}= 999 F, C

_{3}= 1000 F and C

_{4}= 10001 F, then I get an answer (767119326 F) and this is much larger than C

_{1}. Any suggestions?

(I realize the capacitances used here are very large, but they are just used to make a point.)