Capacitance of Axon: Calculate Farads

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Homework Help Overview

The discussion revolves around calculating the capacitance of an axon, which is modeled as a parallel plate capacitor. The problem involves parameters such as the dielectric constant, plate area, and thickness of the membrane.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the appropriate formula for capacitance and the significance of the permittivity of free space. There is uncertainty about how to apply the formula given the dielectric constant of the medium.

Discussion Status

Some participants have provided the formula for capacitance and clarified the meaning of the permittivity of free space. However, there remains confusion regarding the application of this formula in the context of the axon's dielectric properties, indicating ongoing exploration of the topic.

Contextual Notes

Participants are navigating the specifics of the problem, including the need to adjust the capacitance formula to account for the dielectric constant of the axon membrane.

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Homework Statement



An axon is the relatively long tail-like part of a neuron, or nerve cell. The outer surface of the axon membrane (dielectric constant = 5, thickness = 1 x 10^-8 m) is charged positively, and the inner portion is charged negatively.

Thus, the membrane is a kind of capacitor. Assuming that an axon can be treated like a parallel plate capacitor with a plate area of 4.70 x 10^-6 m^2, what is its capacitance?

in Farat



Homework Equations





The Attempt at a Solution


here is the equation:
View attachment untitled.bmp

there are other numbers being used as an example. I just don't know what to use for E0 if E = V/R, and I don't have V, so how do i solve this. thanks.

 
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There is a simple formula for the capacitance of a parallel plate capacitor:

[tex] C = \frac{\epsilon_o A}{d}[/tex]
 
Ya thanks for the formula, but i still don't know what E0 is?
 
permittivity of free space! 8.85418782 × 10-12 m-3 kg-1 s4 A2
 
StrongForce said:
permittivity of free space! 8.85418782 × 10-12 m-3 kg-1 s4 A2

yes.. but it won't work in this case, as the medium is different than free space [di-electric constant = k = 5, here]. So the formula will be:

[tex] C = \frac{\epsilon_o kA}{d}[/tex]

where k [in this example] is 5.
 

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