Capacitance of Axon: Calculate Farads

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The discussion focuses on calculating the capacitance of an axon, modeled as a parallel plate capacitor. The relevant formula for capacitance is C = ε₀kA/d, where ε₀ is the permittivity of free space (8.854 x 10^-12 F/m), k is the dielectric constant (5), A is the plate area (4.70 x 10^-6 m²), and d is the membrane thickness (1 x 10^-8 m). Participants clarify that the dielectric constant must be included in the calculation due to the axon's medium being different from free space. The conversation emphasizes understanding the components of the formula to arrive at the correct capacitance value in Farads.
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Homework Statement



An axon is the relatively long tail-like part of a neuron, or nerve cell. The outer surface of the axon membrane (dielectric constant = 5, thickness = 1 x 10^-8 m) is charged positively, and the inner portion is charged negatively.

Thus, the membrane is a kind of capacitor. Assuming that an axon can be treated like a parallel plate capacitor with a plate area of 4.70 x 10^-6 m^2, what is its capacitance?

in Farat



Homework Equations





The Attempt at a Solution


here is the equation:
View attachment untitled.bmp

there are other numbers being used as an example. I just don't know what to use for E0 if E = V/R, and I don't have V, so how do i solve this. thanks.

 
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There is a simple formula for the capacitance of a parallel plate capacitor:

<br /> C = \frac{\epsilon_o A}{d}<br />
 
Ya thanks for the formula, but i still don't know what E0 is?
 
permittivity of free space! 8.85418782 × 10-12 m-3 kg-1 s4 A2
 
StrongForce said:
permittivity of free space! 8.85418782 × 10-12 m-3 kg-1 s4 A2

yes.. but it won't work in this case, as the medium is different than free space [di-electric constant = k = 5, here]. So the formula will be:

<br /> C = \frac{\epsilon_o kA}{d}<br />

where k [in this example] is 5.
 
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