1. A 2.05 µF capacitor (#1) is charged to 901 V and a 6.68 µF capacitor (#2) is charged to 671 V. These capacitors are then disconnected from their batteries. Next the positive plates are connected to each other and the negative plates are connected to each other. What will be the potential difference across each and the charge on each 2. C=8.85e10(A/d), Q=v/c, 3. The attempt at a solution Im not really sure where to start, i think that in the end both voltages should be the same but not sure how to get it there. Any help would be great, thanks.