Capacitor problem with a beam balance -- balancing after changing the charge

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SUMMARY

The discussion focuses on a problem involving a parallel plate capacitor supported by a beam balance, specifically addressing the calculation of additional mass required to maintain balance after applying a voltage of 5000V. The capacitor plates have a distance of 5mm and an area of 100 sq.cm. The equation used in the analysis is derived from the principle of virtual work, expressed as Q²d/2A × ε₀ = mg, where ε₀ represents the permittivity of free space. Participants are encouraged to explore the derivation of this equation and its application in the context of the problem.

PREREQUISITES
  • Understanding of parallel plate capacitor fundamentals
  • Familiarity with the principle of virtual work
  • Knowledge of electrostatics, specifically voltage and charge relationships
  • Basic mechanics related to balance and mass
NEXT STEPS
  • Research the derivation of the equation Q²d/2A × ε₀ = mg
  • Study the principles of virtual work in mechanical systems
  • Learn about the effects of voltage on capacitor behavior
  • Explore applications of beam balances in experimental physics
USEFUL FOR

Physics students, electrical engineers, and anyone involved in experimental design or electrostatics who seeks to understand the relationship between electric charge and mechanical balance.

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New poster has been reminded to show the Relevant Equations and their Attempt at the Solution in schoolwork posts
The lower plate of a parallel plate capacitor is supported on a rigid rod.The upper plate is suspended from one end of a balance.The two plates are joined together by a thin wire and subsequently disconnected.The balance is then counterpoised.Now a voltage V= 5000V is applied between the plates.The distance between the plates is d=5mm and the area of each plate is A=100sq.cm. Then find out additional mass placed to maintain balance.All the elements other than plates are massless and non conducting.

Homework Equations

The Attempt at a Solution

 

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I don't see an attempt at a solution. Hint - try using the principle of virtual work.
 
phyzguy said:
I don't see an attempt at a solution. Hint - try using the principle of virtual work.
I had done Q^2d/2A ×apsilonnot =mg
 
Where did that equation come from?
 

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