Capacitor Voltage Homework: Vo(0), v(infinity), & R

[princejan7]

Homework Statement

http://postimg.org/image/4m0huqxpj/

Homework Equations

v(t)=v(infinity)+ [v(0) - v(infinity)]^e(-t/RC)

The Attempt at a Solution

I found Vo(0) to be 8V, but I'm not sure about about v(infinity) and R

If the switch is at B and the capacitor is an open circuit at steady state, then shouldn't the resistance be the addition of the parallel combination of 40k and 30k and the 20k
however, the solution for R is given as 12and for v(infinity), I don't know know what to do

 

[gneill]

When the switch moves to position B the 40 k resistor will have one end open, so no current can flow through it and it will play no further role in the circuit.

For v_∞, remove the capacitor from the circuit and determine the potential across the points where it was connected.

 

[princejan7]

When the switch moves to position B the 40 k resistor will have one end open, so no current can flow through it and it will play no further role in the circuit.

For v_∞, remove the capacitor from the circuit and determine the potential across the points where it was connected.

thanks, I have another question

http://postimg.org/image/m6c1rf60h/

why is there no mention of i(infinity) for this?
is the current through the inductor zero at steady state with the switch closed?


i(t)=i(infinity)+ [i(0) - i(infinity)]^e(-Lt/R)

 

[NascentOxygen]

The inductor current falls away, becoming 0 at t=∞

The switch directs to ground all current from the battery, so the battery has no influence over the inductor once the switch closes.

 

[gneill]

thanks, I have another question

http://postimg.org/image/m6c1rf60h/

why is there no mention of i(infinity) for this?
is the current through the inductor zero at steady state with the switch closed?


i(t)=i(infinity)+ [i(0) - i(infinity)]^e(-Lt/R)

For a NEW question, why not make a NEW thread? Did you solve the problem of the current thread?