Charged Capacitors - Homework Equations & Attempt at Solution

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Homework Help Overview

The problem involves two capacitors, a 10nF and a 20nF, charged to different voltages and connected in a specific configuration with a resistor. The goal is to derive equations for the total voltage across the resistor and the voltages across each capacitor over time.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to establish the initial voltage difference and questions the appropriate resistance value to use for each capacitor in the context of their connection. Some participants suggest deriving a differential equation for the current based on the circuit setup.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and the application of relevant equations. There is a suggestion to derive a differential equation tailored to the specific circuit configuration presented.

Contextual Notes

Participants note the potential ambiguity in the application of existing equations to this specific setup and the need for clarification on the resistor's role in the circuit.

jh001
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Homework Statement


A 10nF and 20nF capacitor is independently charged to respectively 40V and 50V. The positive sides of the two capacitors are connected, and a 1kΩ resistor is connected across the negative terminals. Find equations for total voltage VT(t) across the resistor and voltages across each capacitor V1(t) and V2(t)

Homework Equations


V(t)=V0e-t/RC

The Attempt at a Solution


It seems VT(0) = 50-40 = 10V.
Can we use VT(t)=V2(t)-V1(t), since the capacitors are connected positive to positive? In that case what value for R do we use for each capacitor?
 
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There may be some law you can appeal to, but it isn't hard to work out from first principles. (I.e., obtain a differential equation for the current.)
 
"work out from first principles" is a bit cryptic/generic and not really helpful. The equation I gave IS in effect a differential equation (well, the solution to one) Can you please elaborate?
 
jh001 said:
"work out from first principles" is a bit cryptic/generic and not really helpful. The equation I gave IS in effect a differential equation (well, the solution to one) Can you please elaborate?
Yes, it's the solution to a differential equation, but you don't know how to apply it because the equation was for a simpler set-up. I'm proposing writing out the differential equation for the set-up in the question and solving that in the same way. You can then be confident in how to apply it here. (It turns out to be just what you might have guessed.)
 

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