# Capacitor with two angled dielectric materials

1. Oct 15, 2012

### Siberion

1. The problem statement, all variables and given/known data
Find the capacitance of the capacitor shown in the figure. Asume H << L.
http://imageshack.us/a/img39/1935/capacitor.png [Broken]

2. Relevant equations

Capacitance of a plate parallel capacitor with a dielectric material e: eA/H where A denotes the area of the plate, and H the separation between plates

3. The attempt at a solution
My thoughts:

The line separating the dielectric materials can be written as f(x)=Hx/L (I rotated the system so the line starts in the origin)
The system can be considered as multiple parallel capacitors in which the proportion of the dielectric changes at the rate given by the linear equation.
First, I calculated the differential capacitance of two capacitors in series, whose lenght is dx. Their capacitances are given by:

$$C1= \frac{e1Ldx}{H-\frac{Hx}{L}}$$
$$C2= \frac{e2Ldx}{\frac{Hx}{L}}$$

After getting the equivalent capacitance, I integrated from 0 to L, hoping to get the total capacitance of the system.
Thing is, when I assume e1=e2, I don't get the capacitance of a normal plate parallel capacitor with one dielectric material.

I really want to know if the logic of my process is okay, because I've tried about 5 times to check if calculus are done right.

Sorry for my english and the simplicity of my explanation, I'll try to explain further when I get a little more time.