Capacitors - energy stored vs work done

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Homework Help Overview

The discussion revolves around the energy stored in a capacitor and the work done by a battery in charging it. The specific case involves a 180 microfarad capacitor charged to a potential difference of 100 volts, leading to calculations of energy stored and work done, which appear to differ according to the original poster's findings.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the energy stored in the capacitor and the work done by the battery, questioning why these values differ. There is a discussion about energy dissipation during the charging process and whether the energy required to charge should equal the energy stored.

Discussion Status

Participants are actively engaging with the concepts, with some questioning the assumptions about energy loss during charging. There is no explicit consensus, but references to calculations and similar discussions indicate a productive exploration of the topic.

Contextual Notes

Participants mention a lack of prior instruction on this topic, indicating that the original poster is revising for an exam rather than completing assigned homework. There are references to external resources for further clarification.

RK1992
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this isn't homework, I am doing revision for an exam :)

a 180 microfarad capacitor is charged so that is has a PD of 100v across the plates. i calculate the energy stored as 0.5cv² = 0.9J

the question then asks me to calculate the work done by the battery in charging the capacitor. the mark scheme says that i should use W = QV = CV² and should therefore get 1.8J

why is the work done in charging the capacitor different to the energy stored on it? i have never heard my teacher mention this fact in lessons, so i seriously have no idea where this has come from.. where does this equation come from? thanks
 
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RK1992 said:
this isn't homework, I am doing revision for an exam :)

So work you're doing at home, but not homework? :wink:
a 180 microfarad capacitor is charged so that is has a PD of 100v across the plates. i calculate the energy stored as 0.5cv² = 0.9J

the question then asks me to calculate the work done by the battery in charging the capacitor. the mark scheme says that i should use W = QV = CV² and should therefore get 1.8J

why is the work done in charging the capacitor different to the energy stored on it? i have never heard my teacher mention this fact in lessons, so i seriously have no idea where this has come from.. where does this equation come from? thanks

Well firstly, do you believe the energy it takes to charge the capacitor should equal the energy stored on it?
 
jarednjames said:
So work you're doing at home, but not homework? :wink:
yes, I am a geek :p

jarednjames said:
Well firstly, do you believe the energy it takes to charge the capacitor should equal the energy stored on it?

well no some will dissipate right.. but this isn't charging through a resistor so surely 99% of the energy used charging will be stored?
 
RK1992 said:
yes, I am a geek :p

I meant, work you do at home = homework.
well no some will dissipate right.. but this isn't charging through a resistor so surely 99% of the energy used charging will be stored?

99% is a very specific number you picked there. Do you have the calcs to back it up?

If you work through the calcs you'll see that half the energy is lost when charging.

Here is a similar thread answering the question for you: https://www.physicsforums.com/showthread.php?t=292838
 
jarednjames said:
I meant, work you do at home = homework.
hm i don't think so, its revision :S

jarednjames said:
99% is a very specific number you picked there. Do you have the calcs to back it up?

If you work through the calcs you'll see that half the energy is lost when charging.

Here is a similar thread answering the question for you: https://www.physicsforums.com/showthread.php?t=292838
i just meant most, really..

okay thanks, although I am not sure i understand that thread particularly well :/
 

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