Car Crash on Inclined Circular Racetrack

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The problem involves a car driving on an inclined circular racetrack, with specific parameters regarding the track's angle, dimensions, and friction coefficients. The scenario describes a sudden change in conditions due to an oil slick affecting the car's ability to maintain its position on the track.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster seeks clarification on the location of the "centre of rotation for the track" and its relation to the car's position. Some participants question the formulation of the problem and whether the centre of rotation is synonymous with the centre of the track.

Discussion Status

The discussion is currently focused on clarifying the terminology used in the problem statement. Participants are exploring the implications of the definitions provided and how they relate to the scenario described.

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sparkle123
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"A car is driving on a circular racetrack, which is inclined at an angle of 40 degrees to the horizontal. The centre of rotation for the track lies in the horizontal plane, and is 45 m from the centre fo the racetrack and 5.0 m above ground level. The car's tires have a coefficient of kinetic friction of 0.35. The car is driving at the maximum possible speed to stay in its position on the narrow track. All of a sudden, the car hits an oil slick and the coefficient of friction is reduced to 0. Where, relative to the centre of the track, does the car crash into the ground?"

I need help visualizing this problem. Where exactly is this "centre of rotation for the track"?
Thank you! :)
 
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Hi sparkle123! :smile:

Your problem appears to be badly formulated.
It should say:
"The centre of rotation for the track lies in the horizontal plane, and is 45 m from the car and 5.0 m above ground level."
 
Thanks I like Serena! :)

so centre of rotation for the track = centre of track?
 
Yep! :)
 
Thanks! :)
 

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