Car Displacement & Speed Calculation

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SUMMARY

The discussion focuses on calculating the displacement, average speed, and average velocity of a car traveling a specific route. The car travels 10.0 km north and 8.00 km east, resulting in a total displacement of 12.8 km at an angle of 38.7 degrees east of north. The average speed is calculated to be 0.426 km/min, derived from the total distance covered divided by the time taken. The average velocity, defined as displacement over time, requires further clarification in the discussion.

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A car travels 10.0km due north, then 8.00km due east, the total trip taking 30.0 minutes. Find (a) the displacement of the car, (b) the average speed (in m/s), and (c) the average velocity (in m/s)


a) 10^2+8^2=c^2
164=c^2
c=12.8km

tanx=8/10
x=38.7 degrees

12.8km @ 38.7 degrees E of N

b) d=vt
v=d/t
v=12.8/30.0
v=0.426km/min

c) not sure
 
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Average velocity is displacement over time taken.
 

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