Car travelling around a banked corner with friction

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SUMMARY

A car negotiating a banked curve with a radius of 74.0m and an angle of 23 degrees requires specific calculations to determine both the slowest and fastest speeds. The coefficient of static friction is 0.09. The maximum speed was calculated as 19.7 m/s using the equation v^2 = (74)[(tan(23) + 0.09)/(1 - 0.09tan(23))](9.8). To find the slowest speed, the correct formula is v_min = √[(rg(sin(θ) - μcos(θ)) / (cos(θ) + μsin(θ))], which accounts for the direction of frictional forces.

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  • Understanding of circular motion dynamics
  • Familiarity with trigonometric functions (sine, cosine, tangent)
  • Knowledge of friction coefficients and their implications
  • Ability to manipulate and solve algebraic equations
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  • Study the derivation of the equation for minimum speed on a banked curve
  • Learn about the effects of varying the angle of banking on vehicle dynamics
  • Explore the role of friction in circular motion and its impact on vehicle stability
  • Investigate real-world applications of banked curves in road design and racing
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Physics students, automotive engineers, and anyone interested in understanding vehicle dynamics on curved paths.

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The problem:
A car is traveling along a curve having a radius of 74.0m, banked at an angle of theta = 23 deg. The coefficient of static friction is 0.09. What is the slowest speed the car can negotiate the curve?


Relevant equations:
Fc = Fnet
Fc = mv^2/r
Fnet = [(tan(theta) + u)/(1-utan(theta))]mg


The attempt at a solution
v^2 = (74)[(tan23 + 0.09)/(1-0.09tan23)](9.8)
v = (387.92)^0.5
v= 19.70 m/s


This answer isn't being accepted by the online program we use in class and I can't figure out what I'm doing wrong. Any help would be much appreciate
 
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Seems rather unusual for the question to be asking for the slowest speed.
 
I think it means the slowest the car will be able to travel without sliding into the centre - it'll have to be moving fast enough to offset the other forces. That's how I took it at least. Part 2 of the question asks for the fastest speed, I figured I'd just try to figure out part 1 first:)
 
Okay so i just realized that the speed I had found, 19.7 m/s, is for the fastest speed.

Now I have no idea how to solve for the slowest speed
 
You calculated the maximum velocity. You should have calculated the minimum.

v_{min}=\sqrt{\frac{rg(sin\theta -\mu cos\theta)}{cos\theta +\mu sin\theta}}
 
To find your the slowest speed, your force of friction will be pointed the other direction. Redraw your forces. Think of any object (toy car) rolling on a notebook at a certain angle. If it is going really slow, it will start to 'slide' downwards right? It does not have enough speed to keep it at a constant radius. Since it's sliding downward force of friction is pointing up, away from the center.

Solve the same way you did with the maximum speed, where you had force of friction pointing downward (thus keeping the object from flying outwards).
 
The equation worked, which is great, and the explanation was really helpful - I was just going to ask where the equation came from when i saw it - so thank you all!
 

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