Cauchy Reimann & Complex functions

Click For Summary
SUMMARY

The discussion focuses on the application of the Cauchy-Riemann equations to the complex function G(s) = 1/(s+1) in the context of Laplace Transforms. The user seeks clarification on deriving the real and imaginary components, Gx and Gy, from the expression G(σ + jω) = 1/(σ + jω + 1). The correct approach involves rationalizing the denominator by multiplying by the complex conjugate, leading to Gx = (σ + 1)/((σ + 1)² + ω²) and Gy = (-ω)/((σ + 1)² + ω²). This method confirms that the function is analytic as it satisfies the Cauchy-Riemann conditions.

PREREQUISITES
  • Understanding of complex variables and functions
  • Familiarity with Laplace Transforms
  • Knowledge of Cauchy-Riemann equations
  • Basic algebraic manipulation of complex numbers
NEXT STEPS
  • Study the derivation of the Cauchy-Riemann equations in detail
  • Learn about the properties of analytic functions in complex analysis
  • Explore rationalization techniques for complex fractions
  • Review Laplace Transform applications in engineering mathematics
USEFUL FOR

Mechanical engineers, students of engineering mathematics, and anyone interested in complex analysis and its applications in Laplace Transforms.

phiby
Messages
74
Reaction score
0
I am a mechanical engineer who hasn't done any mechanical engineering for close to 20 years & hence forgotten all Mechanical Engineering & all Engineering Mathematics.

I need to revise on some Engineering Math now - Calculus, Laplace Transforms etc. I have been doing it for a couple of days.

I am getting stuck in a discussion of Complex Variables & Complex functions in Laplace Transforms.

G(s) = 1/(s+1)

We are trying to check if this satisfies Cachy-Reimann & hence analytic.

This is how the analysis goes in the notes I am referring to

G(σ + jω) = 1/(σ + jω + 1) = Gx + jGy ---------- (1)

From this, the next line says
"where

Gx = (σ + 1)/ ( (σ + 1)2 + ω2)
Gy = (-ω)/( (σ + 1)2 + ω2)
"

I don't see how you get Gx & Gy from (1)

Can someone help?

If this is based on some other Math stuff which I need to study before getting here, do let me know.
 
Physics news on Phys.org
You have
[tex]\frac{1}{\sigma+ 1+ j\omega}[/tex]
and, essentially, you want to "rationalize the denominator".

Multiply both numerator and denominator of that fraction by [itex]\sigma+ 1- j\omega[/itex], the "complex conjugate" of the denominator:
[tex]\frac{1}{\sigma+ 1+ j\omega}\frac{\sigma+ 1- j\omega}{\sigma+ 1- j\omega}[/tex]
In the numerator, we will have, of course, [itex]\sigma+ 1- j\omega[/itex]. In the denominator, we have a product of "sum and difference" which is the "difference of the squares"- [itex](\sigma+ 1+ j\omega)(\sigma+ 1- j\omega)= (\sigma+ 1)^2- (j\omega)^2[/itex][itex]= (\sigma+ 1)^2+ \omega^2[/itex] since [itex]j^2= -1[/itex]

That is, the fraction reduces to
[tex]\frac{\sigma+ 1- j\omega}{(\sigma+1)^2+ \omega^2}[/tex]
Gx and Gy are the real and imaginary parts of that.
 
HallsofIvy said:
You have
[tex]\frac{1}{\sigma+ 1+ j\omega}[/tex]
and, essentially, you want to "rationalize the denominator".

Thank you very much. I was stuck on that for quite some time.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 31 ·
2
Replies
31
Views
12K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K