Center of Gravity/Torque problem

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SUMMARY

The discussion centers on solving a torque and static equilibrium problem involving a uniform plank supported by three ropes. The plank measures 2.00m in length and has a mass of 30.0 kg, with a 700N person positioned 5m from the left end. The participant successfully calculated the tension in the first rope (T1) as 501N and the second rope (T2) as 672N, while determining that the third rope (T3) exerts a force of 384N. The participant utilized the equations for torque and static equilibrium, specifically ∑T = 0 and ∑F = 0, to arrive at these conclusions.

PREREQUISITES
  • Understanding of torque calculations using τ = rFsinθ
  • Knowledge of static equilibrium principles, specifically ∑F = 0
  • Familiarity with resolving forces into components, particularly at angles
  • Basic grasp of the concepts of rotational equilibrium
NEXT STEPS
  • Study the principles of torque and how to apply them in various scenarios
  • Learn about static equilibrium and the conditions required for a system to be in equilibrium
  • Explore how to resolve forces into horizontal and vertical components
  • Practice solving similar problems involving multiple forces and torques
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of torque and static equilibrium problems.

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Homework Statement


A uniform plank of length 2.00m and mass 30.0 kg is supported by three ropes. Find the tension in each rope when a 700N person is 5m from the left end.

Here's the diagram of the problem:
http://img206.imageshack.us/img206/3752/torquere9.png

Homework Equations


\tau = rfsin\vartheta

The Attempt at a Solution


I'm not really sure where to start or what to do except I'm pretty sure that
\sum\tau = 0

thanks for helping out :)
 
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Start by splitting the Tension at 40 degrees into vertical and horizontal components. Then consider what the forces mean if the object is in equilibrium
 
\sumF = 0 if it is in equilibrium. I'm still lost :(. I don't know how to find the forces except the two I already have.
 
Initially, set your pivot somewhere so that you only have one variable to worry about.
 
Thanks :) I was thinking the pivot was in the middle for some reason =\ . Well I got T1 (501N) I know that's correct because I checked in the back. Now I just need the other two.
 
The beam has to be in rotational equilibrium as well as in static equilibrium, so the sum of the forces has to equal zero.
 
I got T2, 672N, but now I'm not quite sure how to get T3. To find T2 I did:

\sumT = (1.5)(700) + (30 * 9.8) - 2T_{2} = 0

I also did that (but a little different) to find T1. The angle for T3 is 180 so to me it seems like there would be no force, but the book says it is 384N

Edit: I just read the last post, I think I'll be able to find T3 in a minute. :)

Edit: Yep, I got it.

\sumF = 0 = 501cos40 - T2

Thanks for the tips, and thanks for not solving it all for me it really helped me out :)
 
Last edited:
If T3 was 0, then the horizontal component of the force of T1 would force the beam to the right and the system would not be in static equilibrium.

You solve rotational equilibrium aspects of the system using torques, and you solve static equilibrium aspects of the system using forces.
 
Snazzy, do you have AIM by any chance? I have another problem that I'm too stupid to figure out and it would be awesome if you could help. I was gone from school for a week but I have to turn this all in on Monday and I just have a couple questions. :)
 
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I don't have AIM but you can just post here or PM me.
 

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