Center of Mass and Moment of Inertia

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SUMMARY

The discussion focuses on calculating the center of mass and moment of inertia for a system of mass points. The masses and their positions are defined as follows: M1 = 1kg at (1i + 0j) m, M2 = 2kg at (4i + 0j) m, and M3 = 3kg at (6i + 0j) m, resulting in a total mass of 6kg. The center of mass is calculated to be at (13/3 m, 0 m), while the moment of inertia about the center of mass and parallel to the y-axis is determined to be approximately 112.67 kgm². The initial calculations were incorrect, prompting further discussion for clarification.

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Homework Statement



Find the center of mass of the collection of mass points in Figure P.12 and then find the moment of inertia of the system about an axis through the center of mass and parallel to the y-axis.


Homework Equations



Center of Mass
Moment of Inertia

The Attempt at a Solution



M1 = 1kg, r1 = (1i + 0j) m
M2 = 2kg, r2 = (4i + 0j) m
M3 = 3kg, r3 = (6i + 0j) m
Mass total = 6kg

X of CM = 1/6 (0 + 8 + 18) = 13/3 m
Y of CM = 1/6 (0 + 0 + 0) = 0 m

I = mR^{2}
I = 6 (4.333)^{2}
I = 112.6667 kgm^{2}

The answer was wrong. Thanks for the help
 

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moving it up
 
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I wouldn't keep bumping this thread until your attachment has been approved. ;)
 

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