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Center of Mass & Displacement Question

  1. Mar 11, 2009 #1
    1. The problem statement, all variables and given/known data
    A big olive (m = 0.051 kg) lies at the origin of an xy coordinate system, and a big Brazil nut (M = 0.56 kg) lies at the point (0.81, 3.0) m. At t = 0, a force Fo = (2.6 + 1.7) N begins to act on the olive, and a force Fn = (-4.4 -3.4) N begins to act on the nut.


    2. Relevant equations
    What is the (a)x and (b)y displacement of the center of mass of the olive-nut system at t = 5.6 s, with respect to its position at t = 0?


    3. The attempt at a solution
    Okay, so far, I found X center of mass, and Y center of mass. (0.742,2.75)
    I don't know what to do afterwards.
    I tried combining the forces, resulting in a Fnetx and Fnety.
    So... now... me lost >.< Can someone give me a little help please.
     
  2. jcsd
  3. Mar 11, 2009 #2

    LowlyPion

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    If you have the net force resolved in x,y and the total mass, then doesn't that determine the acceleration in x,y of the CoM?
     
  4. Mar 11, 2009 #3
    Yes, so.. er this is where I get confused.
    Should I just stick the acceleration in x and y into the formula
    x = x0 + .5at^2 ?? with the x being the 0.742 and then 2.75 to find the final x,y?
    It sounds right but I just seem to doubt it.
     
  5. Mar 11, 2009 #4

    LowlyPion

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    I'd forge ahead.

    Since they want displacement of the center of mass, whatever the initial position of the CoM when the olive-nut salad was at rest would be 0 for purposes of calculating displacement of CoM from the constant acceleration.
     
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