# Center of Mass & Displacement Question

1. Mar 11, 2009

### ChazyChazLive

1. The problem statement, all variables and given/known data
A big olive (m = 0.051 kg) lies at the origin of an xy coordinate system, and a big Brazil nut (M = 0.56 kg) lies at the point (0.81, 3.0) m. At t = 0, a force Fo = (2.6 + 1.7) N begins to act on the olive, and a force Fn = (-4.4 -3.4) N begins to act on the nut.

2. Relevant equations
What is the (a)x and (b)y displacement of the center of mass of the olive-nut system at t = 5.6 s, with respect to its position at t = 0?

3. The attempt at a solution
Okay, so far, I found X center of mass, and Y center of mass. (0.742,2.75)
I don't know what to do afterwards.
I tried combining the forces, resulting in a Fnetx and Fnety.
So... now... me lost >.< Can someone give me a little help please.

2. Mar 11, 2009

### LowlyPion

If you have the net force resolved in x,y and the total mass, then doesn't that determine the acceleration in x,y of the CoM?

3. Mar 11, 2009

### ChazyChazLive

Yes, so.. er this is where I get confused.
Should I just stick the acceleration in x and y into the formula
x = x0 + .5at^2 ?? with the x being the 0.742 and then 2.75 to find the final x,y?
It sounds right but I just seem to doubt it.

4. Mar 11, 2009