Center of mass for a function defined body

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Homework Help Overview

The problem involves finding the x-coordinate of the center of mass for a uniform plate defined by the function y(x) = 4a + x²/a, with a specified length on the x-axis and density. The context is rooted in the study of center of mass in physics.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to derive the center of mass using integration and expresses uncertainty about the correctness of their approach. Some participants provide estimates for the center of mass based on geometric reasoning, while others confirm or question the calculations presented.

Discussion Status

The discussion includes various attempts to calculate the center of mass, with some participants providing numerical results and others suggesting that the original poster's method may be on the right track. There is no explicit consensus, but multiple interpretations and calculations are being explored.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available for discussion. The density of the plate and the specific function defining its shape are key assumptions being examined.

Redoctober
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Homework Statement



The upper side of a uniform plate of thickness w is given by a function y(x) = 4a+x^2/a. Length of this plate on the x-axis is a . Find x coord of the center of mass of this object, with respect to the origin O . Take density of the plate as p

The Attempt at a Solution



Y(x)= 4a+(x^(2))/a

Can be restated as w.dA=w(4a+(x^(2))/a).dx
therefore using
w.dA.p=dm
w(4a+(x^(2))/a).dx.p=dm

distance from O to CoM qouted as S
will be S= 1/M∫x.dm
S=1/M∫x.w(4a+(x^(2))/a).p.dx
S=1/M.w.p∫(4ax+(x^3)/a).dx

therefore finally , integrating from x=0 to x=a

S=1/M.w.p(2a^3+(a^3)/4)
Mass M can be substituted by = p.w.∫1.dA = p.w.∫y(x).dx from 0 to a

Is this is correct ?! :) Thanks in advance

:)

 
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You have roughly a rectangle of width a and height 4a. The center of mass you get should be close to (a/2,2a)? Did you get an answer close to this?
 
I did it for the x distance from the origin , i got 27/52*a which is about o.519a i.e nearly 1/2a
 
Redoctober said:
I did it for the x distance from the origin , i got 27/52*a which is about o.519a i.e nearly 1/2a

it is correct.

ehild
 

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