Center of Mass of a Triangle (uniform)

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SUMMARY

The center of mass of an equilateral triangle is located at a distance of 2/3 from any vertex along the median. This centroid can be calculated using the average of the coordinates of the triangle's vertices, specifically (Σx/3, Σy/3). The centroid lies on the line connecting the midpoints of two sides of the triangle. A practical method to visualize this involves dividing the triangle into right triangles and analyzing the intersection points after rotating the triangle.

PREREQUISITES
  • Understanding of centroid and center of mass concepts
  • Familiarity with equilateral triangles and their properties
  • Basic knowledge of coordinate geometry
  • Ability to perform trigonometric calculations, specifically using arc-tangent
NEXT STEPS
  • Study the properties of centroids in various geometric shapes
  • Learn about the application of medians in triangle geometry
  • Explore trigonometric functions and their applications in geometry
  • Investigate graphical tools for visualizing geometric concepts, such as GeoGebra
USEFUL FOR

Students studying geometry, educators teaching triangle properties, and anyone interested in understanding the mathematical principles behind centroids and centers of mass.

hms.tech
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Homework Statement



Where exactly is the center of mass of a triangle ?
the file attached shows a diagram of a triangle which is equilateral, and the blue spots are the mid-points of each side.



Homework Equations



a distance = 2/3 from the vertex (along the median)


The Attempt at a Solution



I think the Midpoint will be equal to (2h)/3 from the top vertex.
But here is the real problem, is this Center of mass gonnah lie on the Yellow line passing through the mid points of two sides of the triangle ?
 

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hms.tech said:
I think the Midpoint will be equal to (2h)/3 from the top vertex.
But here is the real problem, is this Center of mass gonnah lie on the Yellow line passing through the mid points of two sides of the triangle ?

It does, the centroid is an average of the three coordinates, ( (stigma x) /3, (sigma y)/3). since its an equilateral triangle, the angles are all the same, and will all have the same terminal vector of 30 degrees (~0.5 rad) with equal length

A good way to see it is (using a triangle of 2 unit length sides)

cut the equilateral triangle into a right triangle (results in legs of 1, sqrt(3) and a hypotenuse of 2), taking the arc-tangent (opposite over adjacent) of 30 degrees, and rearranging to solve for the opposite (height) with an adjacent (run) length of 1 give you the height. Then rotate the equilateral triangle 120 degrees (360/3) and again bisect to create the right triangle. Do the same thing after rotating the triangle another 120 degrees. The lines should intersect at the same location.


Hope it helps
Joe


an external link to visualize it:
http://www.easycalculation.com/analytical/learn-centroid.php
 

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