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Center of Mass of a Triangle (uniform)

  1. Oct 5, 2012 #1
    1. The problem statement, all variables and given/known data

    Where exactly is the center of mass of a triangle ?
    the file attached shows a diagram of a triangle which is equilateral, and the blue spots are the mid-points of each side.



    2. Relevant equations

    a distance = 2/3 from the vertex (along the median)


    3. The attempt at a solution

    I think the Midpoint will be equal to (2h)/3 from the top vertex.
    But here is the real problem, is this Center of mass gonnah lie on the Yellow line passing through the mid points of two sides of the triangle ?
     

    Attached Files:

    Last edited: Oct 5, 2012
  2. jcsd
  3. Oct 5, 2012 #2
    It does, the centroid is an average of the three coordinates, ( (stigma x) /3, (sigma y)/3). since its an equilateral triangle, the angles are all the same, and will all have the same terminal vector of 30 degrees (~0.5 rad) with equal length

    A good way to see it is (using a triangle of 2 unit length sides)

    cut the equilateral triangle into a right triangle (results in legs of 1, sqrt(3) and a hypotenuse of 2), taking the arc-tangent (opposite over adjacent) of 30 degrees, and rearranging to solve for the opposite (height) with an adjacent (run) length of 1 give you the height. Then rotate the equilateral triangle 120 degrees (360/3) and again bisect to create the right triangle. Do the same thing after rotating the triangle another 120 degrees. The lines should intersect at the same location.


    Hope it helps
    Joe


    an external link to visualize it:
    http://www.easycalculation.com/analytical/learn-centroid.php
     
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