Center of Mass: Plate with hole

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SUMMARY

The discussion focuses on calculating the center of mass of a uniform circular plate with a hole. The plate has a radius of 14 cm, while the hole has a radius of 2 cm, positioned 4 cm from the origin along the x-axis. The center of mass formula used is (m1x1 + m2x2) / (m1 + m2), where m1 and m2 represent the masses of the plate and the hole, respectively. The challenge lies in conceptualizing the plate with the hole as two uniform disks to accurately determine the new center of mass.

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Homework Statement



A uniform circular plate of radius 14 cm has a circular hole of radius 2 cm cut out of it. The center of the plate is at the origin of the coordinate system and the center of the hole is located along the x-axis a distance 4 cm from the origin. What is the position of the center of mass of the plate with the hole in it?

Homework Equations



Center of Mass (x)= (m1x1+m2x2)/(m1+m2)

The Attempt at a Solution


This one has me confused. I know that the hole will move the center of mass, but I'm not sure how. Any help would be appreciated! Thanks!
 
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Finding the center of mass of two uniform disks would be easy (I hope you'll agree). How can you represent the plate with hole as two uniform disks? Hint: 1 - 1 = 0.
 

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