Center Tapped Full-Wave Rectifier minimum Io rating?

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SUMMARY

The minimum Io rating for a Center Tapped Full-Wave Rectifier is calculated using the formula Io = IAVE x 1.2. The original poster initially miscalculated but confirmed that the formula is indeed correct. This calculation is essential for ensuring the rectifier operates within safe limits and avoids potential damage.

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Electrical engineers, students studying circuit design, and anyone involved in power electronics will benefit from this discussion.

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http://img26.imageshack.us/img26/3844/fullwave.jpg

Just as the title states I am having trouble calculating the minimum Io rating in a Center Tapped Full-Wave Rectifier. I thought it was I AVE x 1.2 but that has not seemed to give me the right answer. I would appreciate any help. (The scan is from an old homework assignment).
 
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Never mind it is I ave x 1.2. I just had my calculation wrong.
 

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