Centre of Pressure: Explained and Examined

  • Context: Graduate 
  • Thread starter Thread starter marellasunny
  • Start date Start date
  • Tags Tags
    Pressure
Click For Summary
SUMMARY

The centre of pressure (CP) in aerodynamics is analogous to the center of mass, representing where the lift force acts on an aircraft's wing. The discussion highlights the impact of air-brakes on the CP of a P-28 fighter, indicating that they alter pressure distribution to enhance airflow stability at high speeds. Mathematically, curl is represented as \text{curl}(\vec{V}) = \vec{\nabla} \times \vec{V}, which is a differential formulation that simplifies the analysis of fluid dynamics. Understanding the relationship between curl, gradient, and divergence is crucial for engineers working with fluid mechanics.

PREREQUISITES
  • Understanding of aerodynamics and the concept of centre of pressure
  • Familiarity with vector calculus, specifically curl and gradient
  • Knowledge of fluid dynamics principles
  • Experience with line integrals in engineering contexts
NEXT STEPS
  • Study the effects of air-brakes on aircraft performance and stability
  • Learn about the mathematical derivation of curl and its applications in fluid dynamics
  • Explore the relationship between pressure distribution and lift in aerodynamics
  • Investigate the use of gradient and divergence in engineering problems
USEFUL FOR

Aerospace engineers, fluid dynamics researchers, and students studying aerodynamics and vector calculus will benefit from this discussion.

marellasunny
Messages
245
Reaction score
3
Is centre of pressure the same way they represent curl in mathematics ? i.e representation of pressure condensed to a single point?

Also,on a tv show,the presenter said this about the air-brakes on a P-28 fighter,"The air-brakes change the centre of pressure thereby allowing the wind-flow to stick at high speeds".What does he mean by this?
ASIDE:Since I guess the representation of centre of pressure is pretty similar to curl,could someone please tell me why mathematicians use the gradient to represent curl?

As a engineer,I'm more used to seeing exercises where curl is calculated using the position vector 'dr' and then taking the line integrals.How can I prove that the gradient x field=line integral stuff ?
Thanks.
 
Last edited:
Physics news on Phys.org
Center of pressure is like a center of mass. In aircraft it is kinda where the wing's lift appears to be acting.
http://www.grc.nasa.gov/WWW/k-12/airplane/cp.html

The description in the documentary sounds like garbled rubbish to me. Clearly the air-brake changes the pressure distribution dramatically giving you a lot of drag which could be described as making the air stick ...

AFAIK. mathematicians represent curl as, well, curl. You mean [itex]\text{curl}(\vec{V}) = \vec{\nabla} \times \vec{V}[/itex]? This is the differential form of the integral equations you are used to - they are easier to use in general. Multiply it out and see what happens.

Gradient is like this: [itex]\text{grad}V=\nabla V[/itex] and the other one is the divergence: [itex]\text{div}(\vec{V}) = \vec{nabla}\cdot\vec{V}[/itex]
 
Last edited:

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
3K
  • Poll Poll
  • · Replies 1 ·
Replies
1
Views
3K
  • Poll Poll
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 3 ·
Replies
3
Views
16K
  • · Replies 3 ·
Replies
3
Views
861
Replies
3
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 4 ·
Replies
4
Views
9K