Centrifugal/Reciprocating Pump Efficiency

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SUMMARY

The discussion focuses on calculating the efficiency of a centrifugal pump and a reciprocating pump used to pump 1500 m³ of liquid daily through a total head of 10 m. The centrifugal pump, powered by a 5 kW motor, achieves a discharge rate of 2.0 m³/min and an efficiency of 71.2%. The reciprocating pump, driven by a 3.5 kW motor, has a discharge rate of 1.75 m³/min. The participants emphasize the importance of knowing the electrical input power and motor efficiency for accurate overall efficiency calculations.

PREREQUISITES
  • Understanding of pump efficiency calculations
  • Familiarity with hydraulic principles and power equations
  • Knowledge of centrifugal and reciprocating pump operations
  • Basic electrical engineering concepts related to motor efficiency
NEXT STEPS
  • Research "Centrifugal pump efficiency calculations" for detailed methodologies
  • Study "Reciprocating pump performance metrics" to compare with centrifugal pumps
  • Learn about "Pump curves and manufacturer specifications" for real-world applications
  • Investigate "Motor efficiency impact on pump performance" for comprehensive analysis
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Engineers, mechanical designers, and students in fluid mechanics or pump technology who are involved in pump selection, efficiency analysis, and performance optimization.

Mingsliced
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Homework Statement



It is proposed to pump 1500 m3 of a liquid (density 1100 kg m–3) each day through a total head of 10 m (including all losses) by using either a centrifugal pump or a reciprocating pump.

The centrifugal pump discharges 2.0 m3 min–1 when driven by an electric motor supplying a power of 5 kW.

The reciprocating pump has a discharge rate of 1.75 m3 min–1 when driven by an electric motor supplying 3.5 kW.

1) Calculate the efficiency of the pumps.

Homework Equations



Po = QvρGHP

ηp = Po/PI
ηm = PI/Pe
ηo = Po/Pe

The Attempt at a Solution


[/B]
Data Collection

ρ = 1100 kg m–3
G = 9.81 m/s-1
Hp = 10m

Convert flowrate from m3/min-1 to m3/sec-1:

2/60 = 0.033m3/sec-1 for the centrifugal pump.

1.75/60 = 2/60 = 0.029m3/sec-1 for the reciprocating pump.

Calculate output power of the centrifugal pump:

Po = QvρGHP

Po = 0.033 * 1100 * 9.81 * 10

Po = 3561.03 Watts

Calculate centrifugal pump efficiency:

ηp = Po/PI * 100

ηp = 3561.03/5000 * 100

ηp = 0.712 * 100

ηp = 71.2% efficiency

I'm a little bit stumped from this point on as I cannot calculate the overall efficiency of each pump without knowing the electrical input power, Pe or even the motor efficiency. Should I assume that the motor is running at 100% efficiency and that the electrical input power Pe is the same as the input power to pump PI?

If not, is there a way that I can calculate Pe without knowing the overall/motor efficiency?

Cheers!
 
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Mingsliced said:
I'm a little bit stumped from this point on as I cannot calculate the overall efficiency of each pump without knowing the electrical input power, Pe or even the motor efficiency. Should I assume that the motor is running at 100% efficiency and that the electrical input power Pe is the same as the input power to pump PI?

If not, is there a way that I can calculate Pe without knowing the overall/motor efficiency?

Cheers!

In the real world, we consult the manufacturer. They have this pump curve which are based on the actual test of the size and other essential parameters of pumps and you have corresponding plots for hydraulic efficiency, might as well the minimum electrical power or motor match with the corresponding pump. I hope this helps.
 
Mingsliced said:
I'm a little bit stumped from this point on as I cannot calculate the overall efficiency of each pump without knowing the electrical input power, Pe or even the motor efficiency. Should I assume that the motor is running at 100% efficiency and that the electrical input power Pe is the same as the input power to pump PI?

If not, is there a way that I can calculate Pe without knowing the overall/motor efficiency?
Are you being asked to calculate the efficiency of the pump, or the motor-pump unit?
For both cases, the power delivered to the pump by the motor is given.
 

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