Centripetal acceleration geometry

Click For Summary

Discussion Overview

The discussion revolves around the geometric aspects of centripetal acceleration in uniform circular motion, specifically focusing on proving the relationship \(\Delta V/V = s/R\). Participants explore the geometric properties of right triangles formed by velocity vectors and arc lengths, as well as the implications of the inscribed angle theorem.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant seeks to demonstrate that the arc length \(s\) forms a right triangle with the change in velocity \(\Delta V\) in uniform circular motion.
  • Another participant emphasizes the need to consider the different units of distances and velocities when solving geometry problems involving circular motion.
  • A participant mentions using the angle \(\phi\) (the angle of the arc traveled) and the angle \(\phi'\) (the angle between the old and new velocity vectors) to derive the relationship \(\Delta V/V = s/R\).
  • One participant expresses difficulty in proving that the angle formed by two tangents to the circle must inscribe a 180-degree arc and be a right angle.
  • A reference to the inscribed angle theorem is provided, stating that an inscribed angle of 90 degrees requires a central angle of 180 degrees, which corresponds to a diameter.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the geometric proof regarding the relationship between the angles and the properties of the circle. Multiple approaches and interpretations are presented, indicating ongoing uncertainty and exploration of the topic.

Contextual Notes

Some participants note the potential confusion arising from mixing units of distance and velocity in geometric proofs. The discussion also highlights the need for clarity in the relationships between angles and arcs in circular motion.

richardbsmith
Messages
6
Reaction score
0
This is probably a geometry question more that a physics question. I am trying to prove that in uniform circular motion [tex]\Delta[/tex] V[tex]/[/tex]V= s[tex]/[/tex]R.

I am basically trying to show that S forms a right triangle with [tex]\Delta[/tex]V, when [tex]V{1}[/tex] is added to [tex]V{2}[/tex] as a vector. (This is to demonstrate that the triangles are similar.)

I understand that the angle formed by S and [tex]\Delta[/tex]V is a right angle because it obviously inscribes the diameter. I just cannot seem to find a satisfactory proof that [tex]\Delta[/tex]V must necessarily intersect the circle at the diameter.

Probably not explaining this very well.
 
Physics news on Phys.org
richardbsmith said:
This is probably a geometry question more that a physics question. I am trying to prove that in uniform circular motion [tex]\Delta[/tex] V[tex]/[/tex]V= s[tex]/[/tex]R.

I am basically trying to show that S forms a right triangle with [tex]\Delta[/tex]V, when [tex]V{1}[/tex] is added to [tex]V{2}[/tex] as a vector. (This is to demonstrate that the triangles are similar.)

I understand that the angle formed by S and [tex]\Delta[/tex]V is a right angle because it obviously inscribes the diameter. I just cannot seem to find a satisfactory proof that [tex]\Delta[/tex]V must necessarily intersect the circle at the diameter.

Probably not explaining this very well.
If you are solving geometry problems with both distances and velocities involved, then you
are probably making a mistake: remember that they have different units! (unless you study relativistic theory)
For the mentioned problem you should use formulas:
s=R*fi (fi is angle of the part of orbit traveled in radians)
[tex]\Delta[/tex]V=V*sin(fi') (fi' is the angle between the old and new velocity vector)

Prove that fi=fi' and use sin(fi)=fi (for small angles) and you will get [tex]\Delta[/tex] V[tex]/[/tex]V= s[tex]/[/tex]R
 
Thank you so much for responding. I think though my question which started with uniform motion and delta V, is now simply a geometry question.

I will try to put up a drawing of what I so pitifully tried to explain.

uniformcircularmotion.png


Here is another image with a different angle and size of the tangents.
uniformcircularmotion2.png


I have tried several approaches, but I cannot prove that the angle formed from tangent 1 to tangent 2 to the circle must inscribe a 180 degree arc and must be a right angle.
 
From : http://en.wikipedia.org/wiki/Inscribed_angle_theorem
In geometry, the inscribed angle theorem states that an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle.
So, to get an inscribed angle of 90° you need a central angle of 180°(=diameter line).
 

Similar threads

  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 15 ·
Replies
15
Views
4K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 37 ·
2
Replies
37
Views
5K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 43 ·
2
Replies
43
Views
11K