# Centripetal Acceleration of curved exit ramp

1. Jul 16, 2007

### rash219

Centripetal Acceleration !!!

1. The problem statement, all variables and given/known data

An Engineer wishes to design a curved exit ramp for a toll road in such a way that a car will not have to rely on friction to round the curve without skidding. He does so by banking the road in such a way that the force causing the centripetal acceleration will be supplied by the component of the normal force toward the center of the path
a. Show that for a given speed v and radius r the curve must be banked at an angle $$\Theta$$ such that tan$$\Theta$$ = v^2/r * g

2. Relevant equations

a_c (centripetal acceleration) = V^2 / r
$$\Sigma$$F_y = m * a = 0

3. The attempt at a solution

i hope this diag. makes sense to you.....

According to the question a_c = n * Sin$$\Theta$$ ---- (1)

Then

$$\Sigma$$F_y = m * a = 0
(n * Cos $$\Theta$$) - (m * g) = 0
n = (m * g) / (Cos $$\Theta$$) -------- (2)

substitute 2 in 1 for n

a_c = (m * g) / (Cos $$\Theta$$) * Sin$$\Theta$$
= (m * g) Tan $$\Theta$$

now a_c (centripetal acceleration) = V^2 / r

therefore (V^2 / r) = (m * g) Tan $$\Theta$$

and Tan $$\Theta$$ = (V^2) /(m * g * r)

what am i doing wrong ?.?

2. Jul 16, 2007

### PhanthomJay

Check your equation (1) again, you have identified the centripetal force, not the centripetal acceleration.

3. Jul 16, 2007

### rash219

Thanks!!! worked out right...