Centripetal Force Homework: Solving for F with F = ma

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Homework Help Overview

The discussion centers around calculating centripetal force in a physics lab experiment. The original poster is using the formula F = (mass)(angular speed squared)(average radius) but is encountering unexpectedly large results.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to calculate centripetal force but questions the validity of their results and unit conversions. Participants discuss the definition of angular speed and its conversion to appropriate units.

Discussion Status

Participants are actively engaging in clarifying the calculations and unit conversions. There is a focus on ensuring the angular speed is correctly defined and applied. Some participants are verifying the reasonableness of the calculated force values.

Contextual Notes

The original poster expresses uncertainty about unit conversions and the magnitude of the calculated force. There is a mention of using a motor-driven rotator in the experiment, which may influence the expected values.

jensson
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Homework Statement


I did an expirement in my physics lab on centripetal force. I'm doing the calculations and right now I am calculating the centripetal force using equation: F= (mass)(angular speed squared)(average radius). My answers are coming out to be huge numbers.

ex: (148.8g)(52.70 rev/s)^2(5.494 cm) = 2270217

I'm not even sure what units this converts too.

If I convert g to kilegrams and revolutions/second times 2pi (in radians) then convert cm to meters I get:

(0.1488 kg) (331^2)(0.05494 m ) = 895.7 N

but this is too big as well. what am I doing wrong??
 
Last edited:
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You need the angular speed in the formula. How is it defined? ehild
 
the equation for angular speed we're using is 2pi (n)/elapsed time

n is revolutions

I think I need to convert this to m/s?
 
Last edited:
is 896.2 N reasonable?
 
jensson said:
is 896.2 N reasonable?

almost... It is 890.62 N. One zero is missing.

ehild
 
can you please show me how you got that? because when I put

(0.1488) (331.1^2) (0.05494) that comes out to 896.2 N
 
You are right, I misread something on my calculator.

ehild
 
that seems like a lot of Newtons! This was an experiment in class with a little motor driven rotator.
 

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